What is the general solution for cot(a)-1=0 ?

The general solution for cot(a)-1=0 is a= pi/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cot(a)-1=0

cot (a) - 1 = 0

a = \frac{π}{4} + πn

Degrees

a = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

cot (a) - 1 = 0

Move

1

to the right side

cot (a) - 1 = 0

Add

1

to both sides

cot (a) - 1 + 1 = 0 + 1

Simplify

cot (a) = 1

cot (a) = 1

General solutions for

cot (a) = 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

a = \frac{π}{4} + πn

a = \frac{π}{4} + πn

csc (θ) = - \frac{3}{5}

cos^{2} (β) = \frac{16}{25}, 0 \leq β \leq 2 π

arctan (x) + arctan (\frac{x}{2}) = 90

6 sin (c) + 8 = 0

sin (2 θ) = - \frac{1}{8}, 27 0^{\circ} < θ < 36 0^{\circ}

What is the general solution for cot(a)-1=0 ?
The general solution for cot(a)-1=0 is a= pi/4+pin