What is the general solution for 3sec^2(x)-4=0,0<= x<2pi ?

Q: What is the general solution for 3sec^2(x)-4=0,0<= x<2pi ?

The general solution for 3sec^2(x)-4=0,0<= x<2pi is x= pi/6 ,x=(11pi)/6 ,x=(5pi)/6 ,x=(7pi)/6

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3sec^2(x)-4=0,0<= x<2pi

Solution

3 sec^{2} (x) - 4 = 0, 0 \leq x < 2 π

Solution

x = \frac{π}{6}, x = \frac{11 π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}

Degrees

x = 3 0^{\circ}, x = 33 0^{\circ}, x = 15 0^{\circ}, x = 21 0^{\circ}

Solution steps

3 sec^{2} (x) - 4 = 0, 0 \leq x < 2 π

Solve by substitution

3 sec^{2} (x) - 4 = 0

Let:

sec (x) = u

3 u^{2} - 4 = 0

3 u^{2} - 4 = 0 : u = \frac{2 3}{3}, u = - \frac{2 3}{3}

3 u^{2} - 4 = 0

Move

4

to the right side

3 u^{2} - 4 = 0

Add

4

to both sides

3 u^{2} - 4 + 4 = 0 + 4

Simplify

3 u^{2} = 4

3 u^{2} = 4

Divide both sides by

3

3 u^{2} = 4

Divide both sides by

3

\frac{3 u ^{2}}{3} = \frac{4}{3}

Simplify

u^{2} = \frac{4}{3}

u^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{4}{3}, u = - \frac{4}{3}

\frac{4}{3} = \frac{2 3}{3}

\frac{4}{3}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{4}{3}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{2}{3}

Rationalize

\frac{2}{3} : \frac{2 3}{3}

\frac{2}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{2 3}{3 3}

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{2 3}{3}

= \frac{2 3}{3}

- \frac{4}{3} = - \frac{2 3}{3}

- \frac{4}{3}

Simplify

\frac{4}{3} : \frac{2}{3}

\frac{4}{3}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{4}{3}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{2}{3}

= - \frac{2}{3}

Rationalize

- \frac{2}{3} : - \frac{2 3}{3}

- \frac{2}{3}

Multiply by the conjugate

\frac{3}{3}

= - \frac{2 3}{3 3}

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= - \frac{2 3}{3}

= - \frac{2 3}{3}

u = \frac{2 3}{3}, u = - \frac{2 3}{3}

Substitute back

u = sec (x)

sec (x) = \frac{2 3}{3}, sec (x) = - \frac{2 3}{3}

sec (x) = \frac{2 3}{3}, sec (x) = - \frac{2 3}{3}

sec (x) = \frac{2 3}{3}, 0 \leq x < 2 π : x = \frac{π}{6}, x = \frac{11 π}{6}

sec (x) = \frac{2 3}{3}, 0 \leq x < 2 π

General solutions for

sec (x) = \frac{2 3}{3}

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{6}, x = \frac{11 π}{6}

sec (x) = - \frac{2 3}{3}, 0 \leq x < 2 π : x = \frac{5 π}{6}, x = \frac{7 π}{6}

sec (x) = - \frac{2 3}{3}, 0 \leq x < 2 π

General solutions for

sec (x) = - \frac{2 3}{3}

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{5 π}{6}, x = \frac{7 π}{6}

Combine all the solutions

x = \frac{π}{6}, x = \frac{11 π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}

Popular Examples

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cos^2(θ)= 1/3

cos^{2} (θ) = \frac{1}{3}

Frequently Asked Questions (FAQ)

What is the general solution for 3sec^2(x)-4=0,0<= x<2pi ?
The general solution for 3sec^2(x)-4=0,0<= x<2pi is x= pi/6 ,x=(11pi)/6 ,x=(5pi)/6 ,x=(7pi)/6