What is the general solution for cos(x)= 12/17 ?

The general solution for cos(x)= 12/17 is x=0.78712…+2pin,x=2pi-0.78712…+2pin

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cos(x)= 12/17

cos (x) = \frac{12}{17}

x = 0.78712 \dots + 2 πn, x = 2 π - 0.78712 \dots + 2 πn

Degrees

x = 45.09912 \dots^{\circ} + 36 0^{\circ} n, x = 314.90087 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = \frac{12}{17}

Apply trig inverse properties

cos (x) = \frac{12}{17}

General solutions for

cos (x) = \frac{12}{17}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{12}{17}) + 2 πn, x = 2 π - arccos (\frac{12}{17}) + 2 πn

x = arccos (\frac{12}{17}) + 2 πn, x = 2 π - arccos (\frac{12}{17}) + 2 πn

Show solutions in decimal form

x = 0.78712 \dots + 2 πn, x = 2 π - 0.78712 \dots + 2 πn

x, (d^{3} + d^{2} + 1) y = cos (3 x)

arccos (2 x - 1) = \frac{π}{6}

sin (θ) - cos (\frac{θ}{2}) = 0

tan (x) = \frac{195}{867}

x, cos (q x) = sin (r x)

What is the general solution for cos(x)= 12/17 ?
The general solution for cos(x)= 12/17 is x=0.78712…+2pin,x=2pi-0.78712…+2pin