What is the general solution for 2cot(2x)=4 ?

The general solution for 2cot(2x)=4 is x=(0.46364…)/2+(pin)/2

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2cot(2x)=4

2 cot (2 x) = 4

x = \frac{0.46364 \dots}{2} + \frac{πn}{2}

Degrees

x = 13.28252 \dots^{\circ} + 9 0^{\circ} n

Solution steps

2 cot (2 x) = 4

Divide both sides by

2

2 cot (2 x) = 4

Divide both sides by

2

\frac{2 cot ( 2 x )}{2} = \frac{4}{2}

Simplify

cot (2 x) = 2

cot (2 x) = 2

Apply trig inverse properties

cot (2 x) = 2

General solutions for

cot (2 x) = 2

cot (x) = a \Rightarrow x = arccot (a) + πn

2 x = arccot (2) + πn

2 x = arccot (2) + πn

Solve

2 x = arccot (2) + πn : x = \frac{arccot ( 2 )}{2} + \frac{πn}{2}

2 x = arccot (2) + πn

Divide both sides by

2

2 x = arccot (2) + πn

Divide both sides by

2

\frac{2 x}{2} = \frac{arccot ( 2 )}{2} + \frac{πn}{2}

Simplify

x = \frac{arccot ( 2 )}{2} + \frac{πn}{2}

x = \frac{arccot ( 2 )}{2} + \frac{πn}{2}

x = \frac{arccot ( 2 )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{0.46364 \dots}{2} + \frac{πn}{2}

cos (θ) = \frac{4}{3.3 8 ^{2} + 2 ^{2}}

23 sin (2 θ) = 3

0 = 3 - 2 sin (x)

- 2 sin^{2} (θ) + cos (θ) = - 1

4 cos (θ) = 4 (1 - cos (θ))

What is the general solution for 2cot(2x)=4 ?
The general solution for 2cot(2x)=4 is x=(0.46364…)/2+(pin)/2