What is the general solution for sin(5a)=0 ?

The general solution for sin(5a)=0 is a=(2pin)/5 ,a= pi/5+(2pin)/5

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sin(5a)=0

sin (5 a) = 0

a = \frac{2 πn}{5}, a = \frac{π}{5} + \frac{2 πn}{5}

Degrees

a = 0^{\circ} + 7 2^{\circ} n, a = 3 6^{\circ} + 7 2^{\circ} n

Solution steps

sin (5 a) = 0

General solutions for

sin (5 a) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

5 a = 0 + 2 πn, 5 a = π + 2 πn

5 a = 0 + 2 πn, 5 a = π + 2 πn

Solve

5 a = 0 + 2 πn : a = \frac{2 πn}{5}

5 a = 0 + 2 πn

0 + 2 πn = 2 πn

5 a = 2 πn

Divide both sides by

5

5 a = 2 πn

Divide both sides by

5

\frac{5 a}{5} = \frac{2 πn}{5}

Simplify

a = \frac{2 πn}{5}

a = \frac{2 πn}{5}

Solve

5 a = π + 2 πn : a = \frac{π}{5} + \frac{2 πn}{5}

5 a = π + 2 πn

Divide both sides by

5

5 a = π + 2 πn

Divide both sides by

5

\frac{5 a}{5} = \frac{π}{5} + \frac{2 πn}{5}

Simplify

a = \frac{π}{5} + \frac{2 πn}{5}

a = \frac{π}{5} + \frac{2 πn}{5}

a = \frac{2 πn}{5}, a = \frac{π}{5} + \frac{2 πn}{5}

x, y = 2 sin (x y)

tan (x) cos (x) sin (x) - 1 = 0

sin (2 x) + 3 cos^{2} (x) sin (x) = 0

43 = 8 sin (θ)

7 tan (3 x) = 7

What is the general solution for sin(5a)=0 ?
The general solution for sin(5a)=0 is a=(2pin)/5 ,a= pi/5+(2pin)/5