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Popular Trigonometry >

tan(x)+cot(x)= 5/2

  • Pre Algebra
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Solution

tan(x)+cot(x)=25​

Solution

x=0.46364…+πn,x=1.10714…+πn
+1
Degrees
x=26.56505…∘+180∘n,x=63.43494…∘+180∘n
Solution steps
tan(x)+cot(x)=25​
Subtract 25​ from both sidestan(x)+cot(x)−25​=0
Simplify tan(x)+cot(x)−25​:22tan(x)+2cot(x)−5​
tan(x)+cot(x)−25​
Convert element to fraction: tan(x)=2tan(x)2​,cot(x)=2cot(x)2​=2tan(x)⋅2​+2cot(x)⋅2​−25​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=2tan(x)⋅2+cot(x)⋅2−5​
22tan(x)+2cot(x)−5​=0
g(x)f(x)​=0⇒f(x)=02tan(x)+2cot(x)−5=0
Rewrite using trig identities
−5+2cot(x)+2tan(x)
Use the basic trigonometric identity: tan(x)=cot(x)1​=−5+2cot(x)+2⋅cot(x)1​
2⋅cot(x)1​=cot(x)2​
2⋅cot(x)1​
Multiply fractions: a⋅cb​=ca⋅b​=cot(x)1⋅2​
Multiply the numbers: 1⋅2=2=cot(x)2​
=−5+2cot(x)+cot(x)2​
−5+cot(x)2​+2cot(x)=0
Solve by substitution
−5+cot(x)2​+2cot(x)=0
Let: cot(x)=u−5+u2​+2u=0
−5+u2​+2u=0:u=2,u=21​
−5+u2​+2u=0
Multiply both sides by u
−5+u2​+2u=0
Multiply both sides by u−5u+u2​u+2uu=0⋅u
Simplify
−5u+u2​u+2uu=0⋅u
Simplify u2​u:2
u2​u
Multiply fractions: a⋅cb​=ca⋅b​=u2u​
Cancel the common factor: u=2
Simplify 2uu:2u2
2uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=2u1+1
Add the numbers: 1+1=2=2u2
Simplify 0⋅u:0
0⋅u
Apply rule 0⋅a=0=0
−5u+2+2u2=0
−5u+2+2u2=0
−5u+2+2u2=0
Solve −5u+2+2u2=0:u=2,u=21​
−5u+2+2u2=0
Write in the standard form ax2+bx+c=02u2−5u+2=0
Solve with the quadratic formula
2u2−5u+2=0
Quadratic Equation Formula:
For a=2,b=−5,c=2u1,2​=2⋅2−(−5)±(−5)2−4⋅2⋅2​​
u1,2​=2⋅2−(−5)±(−5)2−4⋅2⋅2​​
(−5)2−4⋅2⋅2​=3
(−5)2−4⋅2⋅2​
Apply exponent rule: (−a)n=an,if n is even(−5)2=52=52−4⋅2⋅2​
Multiply the numbers: 4⋅2⋅2=16=52−16​
52=25=25−16​
Subtract the numbers: 25−16=9=9​
Factor the number: 9=32=32​
Apply radical rule: 32​=3=3
u1,2​=2⋅2−(−5)±3​
Separate the solutionsu1​=2⋅2−(−5)+3​,u2​=2⋅2−(−5)−3​
u=2⋅2−(−5)+3​:2
2⋅2−(−5)+3​
Apply rule −(−a)=a=2⋅25+3​
Add the numbers: 5+3=8=2⋅28​
Multiply the numbers: 2⋅2=4=48​
Divide the numbers: 48​=2=2
u=2⋅2−(−5)−3​:21​
2⋅2−(−5)−3​
Apply rule −(−a)=a=2⋅25−3​
Subtract the numbers: 5−3=2=2⋅22​
Multiply the numbers: 2⋅2=4=42​
Cancel the common factor: 2=21​
The solutions to the quadratic equation are:u=2,u=21​
u=2,u=21​
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of −5+u2​+2u and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=2,u=21​
Substitute back u=cot(x)cot(x)=2,cot(x)=21​
cot(x)=2,cot(x)=21​
cot(x)=2:x=arccot(2)+πn
cot(x)=2
Apply trig inverse properties
cot(x)=2
General solutions for cot(x)=2cot(x)=a⇒x=arccot(a)+πnx=arccot(2)+πn
x=arccot(2)+πn
cot(x)=21​:x=arccot(21​)+πn
cot(x)=21​
Apply trig inverse properties
cot(x)=21​
General solutions for cot(x)=21​cot(x)=a⇒x=arccot(a)+πnx=arccot(21​)+πn
x=arccot(21​)+πn
Combine all the solutionsx=arccot(2)+πn,x=arccot(21​)+πn
Show solutions in decimal formx=0.46364…+πn,x=1.10714…+πn

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Popular Examples

sin(2x)+sqrt(2)cos(x)=0csc(2x)=-sqrt(2)3sin(2x)=-1.76sin(θ)= 5/12sin(a)= 24/25

Frequently Asked Questions (FAQ)

  • What is the general solution for tan(x)+cot(x)= 5/2 ?

    The general solution for tan(x)+cot(x)= 5/2 is x=0.46364…+pin,x=1.10714…+pin
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