What is the general solution for tan(x/2)=-1/(sqrt(3)) ?

The general solution for tan(x/2)=-1/(sqrt(3)) is x=(5pi)/3+2pin

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tan(x/2)=-1/(sqrt(3))

tan (\frac{x}{2}) = - \frac{1}{3}

x = \frac{5 π}{3} + 2 πn

Solution steps

tan (\frac{x}{2}) = - \frac{1}{3}

Simplify

- \frac{1}{3} : - \frac{3}{3}

- \frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= - \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= - \frac{3}{3}

tan (\frac{x}{2}) = - \frac{3}{3}

General solutions for

tan (\frac{x}{2}) = - \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

\frac{x}{2} = \frac{5 π}{6} + πn

\frac{x}{2} = \frac{5 π}{6} + πn

Solve

\frac{x}{2} = \frac{5 π}{6} + πn : x = \frac{5 π}{3} + 2 πn

\frac{x}{2} = \frac{5 π}{6} + πn

Multiply both sides by

2

\frac{x}{2} = \frac{5 π}{6} + πn

Multiply both sides by

2

\frac{2 x}{2} = 2 \cdot \frac{5 π}{6} + 2 πn

Simplify

\frac{2 x}{2} = 2 \cdot \frac{5 π}{6} + 2 πn

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

2 \cdot \frac{5 π}{6} + 2 πn : \frac{5 π}{3} + 2 πn

2 \cdot \frac{5 π}{6} + 2 πn

2 \cdot \frac{5 π}{6} = \frac{5 π}{3}

2 \cdot \frac{5 π}{6}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 π 2}{6}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{10 π}{6}

Cancel the common factor:

2

= \frac{5 π}{3}

= \frac{5 π}{3} + 2 πn

x = \frac{5 π}{3} + 2 πn

x = \frac{5 π}{3} + 2 πn

x = \frac{5 π}{3} + 2 πn

x = \frac{5 π}{3} + 2 πn

u, x = 2 cos (u) cos (v)

cos (θ) = cos (3 θ)

cot (3 θ) = 3

tan (x) = \frac{45}{35}

\frac{62 5 ^{c o s^{2} (x)}}{2 5 ^{c o s (x)}} = 1

What is the general solution for tan(x/2)=-1/(sqrt(3)) ?
The general solution for tan(x/2)=-1/(sqrt(3)) is x=(5pi)/3+2pin