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受欢迎的三角函数 >

sinh^2(x)=2sinh(x)cosh(x)

解答

sinh^{2} (x) = 2 sinh (x) cosh (x)

解答

x = 0

+1

度数

x = 0^{\circ}

求解步骤

sinh^{2} (x) = 2 sinh (x) cosh (x)

使用三角恒等式改写

sinh^{2} (x) = 2 sinh (x) cosh (x)

使用双曲函数恒等式:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 sinh (x) cosh (x)

使用双曲函数恒等式:

sinh (x) = \frac{e ^{x} - e ^{- x}}{2}

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 \cdot \frac{e ^{x} - e ^{- x}}{2} cosh (x)

使用双曲函数恒等式:

cosh (x) = \frac{e ^{x} + e ^{- x}}{2}

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 \cdot \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{x} + e ^{- x}}{2}

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 \cdot \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{x} + e ^{- x}}{2}

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 \cdot \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{x} + e ^{- x}}{2} : x = 0

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 \cdot \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{x} + e ^{- x}}{2}

使用指数运算法则

(\frac{e ^{x} - e ^{- x}}{2})^{2} = 2 \cdot \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{x} + e ^{- x}}{2}

使用指数法则:

a^{b c} = (a^{b})^{c}

e^{- x} = (e^{x})^{- 1}

(\frac{e ^{x} - ( e ^{x} ) ^{- 1}}{2})^{2} = 2 \cdot \frac{e ^{x} - ( e ^{x} ) ^{- 1}}{2} \cdot \frac{e ^{x} + ( e ^{x} ) ^{- 1}}{2}

(\frac{e ^{x} - ( e ^{x} ) ^{- 1}}{2})^{2} = 2 \cdot \frac{e ^{x} - ( e ^{x} ) ^{- 1}}{2} \cdot \frac{e ^{x} + ( e ^{x} ) ^{- 1}}{2}

用

e^{x} = u

改写方程式

(\frac{u - ( u ) ^{- 1}}{2})^{2} = 2 \cdot \frac{u - ( u ) ^{- 1}}{2} \cdot \frac{u + ( u ) ^{- 1}}{2}

解

(\frac{u - u ^{- 1}}{2})^{2} = 2 \cdot \frac{u - u ^{- 1}}{2} \cdot \frac{u + u ^{- 1}}{2} : u = - 1, u = 1

(\frac{u - u ^{- 1}}{2})^{2} = 2 \cdot \frac{u - u ^{- 1}}{2} \cdot \frac{u + u ^{- 1}}{2}

整理后得

\frac{( u ^{2} - 1 ) ^{2}}{4 u ^{2}} = \frac{( u ^{2} - 1 ) ( u ^{2} + 1 )}{2 u ^{2}}

使用分式交叉相乘

\frac{( u ^{2} - 1 ) ^{2}}{4 u ^{2}} = \frac{( u ^{2} - 1 ) ( u ^{2} + 1 )}{2 u ^{2}}

使用分式交叉相乘: 若

\frac{a}{b} = \frac{c}{d}

则

a \cdot d = b \cdot c

(u^{2} - 1)^{2} \cdot 2 u^{2} = 4 u^{2} (u^{2} - 1) (u^{2} + 1)

(u^{2} - 1)^{2} \cdot 2 u^{2} = 4 u^{2} (u^{2} - 1) (u^{2} + 1)

解

(u^{2} - 1)^{2} \cdot 2 u^{2} = 4 u^{2} (u^{2} - 1) (u^{2} + 1) : u = 0, u = - 1, u = 1

(u^{2} - 1)^{2} \cdot 2 u^{2} = 4 u^{2} (u^{2} - 1) (u^{2} + 1)

将

4 u^{2} (u^{2} - 1) (u^{2} + 1)

para o lado esquerdo

(u^{2} - 1)^{2} \cdot 2 u^{2} = 4 u^{2} (u^{2} - 1) (u^{2} + 1)

两边减去

4 u^{2} (u^{2} - 1) (u^{2} + 1)

(u^{2} - 1)^{2} \cdot 2 u^{2} - 4 u^{2} (u^{2} - 1) (u^{2} + 1) = 4 u^{2} (u^{2} - 1) (u^{2} + 1) - 4 u^{2} (u^{2} - 1) (u^{2} + 1)

化简

(u^{2} - 1)^{2} \cdot 2 u^{2} - 4 u^{2} (u^{2} - 1) (u^{2} + 1) = 0

(u^{2} - 1)^{2} \cdot 2 u^{2} - 4 u^{2} (u^{2} - 1) (u^{2} + 1) = 0

因式分解

(u^{2} - 1)^{2} \cdot 2 u^{2} - 4 u^{2} (u^{2} - 1) (u^{2} + 1) : - 2 u^{2} (u + 1) (u - 1) (u^{2} + 3)

(u^{2} - 1)^{2} \cdot 2 u^{2} - 4 u^{2} (u^{2} - 1) (u^{2} + 1)

分解

(u^{2} - 1)^{2} : (u + 1)^{2} (u - 1)^{2}

分解

u^{2} - 1 : (u + 1) (u - 1)

u^{2} - 1

将

1

改写为

1^{2}

= u^{2} - 1^{2}

使用平方差公式:

x^{2} - y^{2} = (x + y) (x - y)

u^{2} - 1^{2} = (u + 1) (u - 1)

= (u + 1) (u - 1)

= ((u + 1) (u - 1))^{2}

使用指数法则:

(ab)^{n} = a^{n} b^{n}

= (u + 1)^{2} (u - 1)^{2}

分解

u^{2} - 1 : (u + 1) (u - 1)

u^{2} - 1

将

1

改写为

1^{2}

= u^{2} - 1^{2}

使用平方差公式:

x^{2} - y^{2} = (x + y) (x - y)

u^{2} - 1^{2} = (u + 1) (u - 1)

= (u + 1) (u - 1)

= 2 u^{2} (u + 1)^{2} (u - 1)^{2} - 4 u^{2} (u + 1) (u - 1) (u^{2} + 1)

因式分解出通项

2 u^{2} (u + 1) (u - 1)

= 2 u^{2} (u + 1) (u - 1) ((u + 1) (u - 1) - 2 (u^{2} + 1))

乘开

(u + 1) (u - 1) - 2 (u^{2} + 1) : - u^{2} - 3

(u + 1) (u - 1) - 2 (u^{2} + 1)

乘开

(u + 1) (u - 1) : u^{2} - 1

(u + 1) (u - 1)

使用平方差公式:

(a + b) (a - b) = a^{2} - b^{2}

a = u, b = 1

= u^{2} - 1^{2}

使用法则

1^{a} = 1

1^{2} = 1

= u^{2} - 1

= u^{2} - 1 - 2 (u^{2} + 1)

乘开

- 2 (u^{2} + 1) : - 2 u^{2} - 2

- 2 (u^{2} + 1)

使用分配律:

a (b + c) = ab + a c

a = - 2, b = u^{2}, c = 1

= - 2 u^{2} + (- 2) \cdot 1

使用加减运算法则

+ (- a) = - a

= - 2 u^{2} - 2 \cdot 1

数字相乘:

2 \cdot 1 = 2

= - 2 u^{2} - 2

= u^{2} - 1 - 2 u^{2} - 2

化简

u^{2} - 1 - 2 u^{2} - 2 : - u^{2} - 3

u^{2} - 1 - 2 u^{2} - 2

对同类项分组

= u^{2} - 2 u^{2} - 1 - 2

同类项相加:

u^{2} - 2 u^{2} = - u^{2}

= - u^{2} - 1 - 2

数字相减:

- 1 - 2 = - 3

= - u^{2} - 3

= - u^{2} - 3

= 2 u^{2} (u + 1) (u - 1) (- u^{2} - 3)

分解

- u^{2} - 3 : - (u^{2} + 3)

- u^{2} - 3

因式分解出通项

- 1

= - (u^{2} + 3)

= - 2 u^{2} (u + 1) (u - 1) (u^{2} + 3)

- 2 u^{2} (u + 1) (u - 1) (u^{2} + 3) = 0

使用零因数法则： If

ab = 0

then

a = 0

or

b = 0

u = 0 or u + 1 = 0 or u - 1 = 0 or u^{2} + 3 = 0

解

u + 1 = 0 : u = - 1

u + 1 = 0

将

1

到右边

u + 1 = 0

两边减去

1

u + 1 - 1 = 0 - 1

化简

u = - 1

u = - 1

解

u - 1 = 0 : u = 1

u - 1 = 0

将

1

到右边

u - 1 = 0

两边加上

1

u - 1 + 1 = 0 + 1

化简

u = 1

u = 1

解

u^{2} + 3 = 0 : u \in R

无解

u^{2} + 3 = 0

将

3

到右边

u^{2} + 3 = 0

两边减去

3

u^{2} + 3 - 3 = 0 - 3

化简

u^{2} = - 3

u^{2} = - 3

x^{2}

在

x

内不能为负

\in R

u \in R 无解

解为

u = 0, u = - 1, u = 1

u = 0, u = - 1, u = 1

验证解

找到无定义的点（奇点）:

u = 0

取

(\frac{u - u ^{- 1}}{2})^{2}

的分母，令其等于零

u = 0

取

2 \frac{u - u ^{- 1}}{2} \frac{u + u ^{- 1}}{2}

的分母，令其等于零

u = 0

以下点无定义

u = 0

因为方程对以下值无定义:

0

u = - 1, u = 1

u = - 1, u = 1

代回

u = e^{x}

，求解

x

解

e^{x} = - 1 : x \in R

无解

e^{x} = - 1

a^{f (x)}

对于

x

不能为零或负值

\in R

x \in R 无解

解

e^{x} = 1 : x = 0

e^{x} = 1

使用指数运算法则

e^{x} = 1

若

f (x) = g (x)

，则

ln (f (x)) = ln (g (x))

ln (e^{x}) = ln (1)

使用对数计算法则:

ln (e^{a}) = a

ln (e^{x}) = x

x = ln (1)

化简

ln (1) : 0

ln (1)

使用对数计算法则:

lo g_{a} (1) = 0

= 0

x = 0

x = 0

x = 0

x = 0

作图

流行的例子

tan(3x)cot(x+40)=1

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sin(2θ)=sqrt(2)sin(θ)