What is the general solution for solvefor y,x=arcsin(y^2) ?

The general solution for solvefor y,x=arcsin(y^2) is y=sqrt(sin(x)),y=-sqrt(sin(x))

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solvefor y,x=arcsin(y^2)

solve for

y, x = arcsin (y^{2})

y = sin (x), y = - sin (x)

Solution steps

x = arcsin (y^{2})

Switch sides

arcsin (y^{2}) = x

Apply trig inverse properties

arcsin (y^{2}) = x

arcsin (x) = a \Rightarrow x = sin (a)

y^{2} = sin (x)

y^{2} = sin (x)

Solve

y^{2} = sin (x) : y = sin (x), y = - sin (x)

y^{2} = sin (x)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = sin (x), y = - sin (x)

y = sin (x), y = - sin (x)

cos^{2} (2 x) + cos (2 x) - \frac{3}{4} = 0

sin^{2} (\frac{x}{2}) = a

cos (θ) = \frac{11}{5}

10 cos (θ) = 4 sin^{2} (θ) + 2

\frac{tan ^{2} ( x ) ( 1 + cot ^{2} ( x ) )}{sec ( x )} = cos (x)

What is the general solution for solvefor y,x=arcsin(y^2) ?
The general solution for solvefor y,x=arcsin(y^2) is y=sqrt(sin(x)),y=-sqrt(sin(x))