What is the general solution for 4-2sin(x)=0 ?

The general solution for 4-2sin(x)=0 is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4-2sin(x)=0

4 - 2 sin (x) = 0

No Solution for x \in R

Solution steps

4 - 2 sin (x) = 0

Move

4

to the right side

4 - 2 sin (x) = 0

Subtract

4

from both sides

4 - 2 sin (x) - 4 = 0 - 4

Simplify

- 2 sin (x) = - 4

- 2 sin (x) = - 4

Divide both sides by

- 2

- 2 sin (x) = - 4

Divide both sides by

- 2

\frac{- 2 sin ( x )}{- 2} = \frac{- 4}{- 2}

Simplify

\frac{- 2 sin ( x )}{- 2} = \frac{- 4}{- 2}

Simplify

\frac{- 2 sin ( x )}{- 2} : sin (x)

\frac{- 2 sin ( x )}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 sin ( x )}{2}

Divide the numbers:

\frac{2}{2} = 1

= sin (x)

Simplify

\frac{- 4}{- 2} : 2

\frac{- 4}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

sin (x) = 2

sin (x) = 2

sin (x) = 2

- 1 \leq sin (x) \leq 1

No Solution for x \in R

sin^{2} (θ) - 2 sin (θ) + 3 = 0

3 tan^{2} (θ) + 3 tan (θ) = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

cos (a) = \frac{24}{25}

sin^{2} (x) = 3 sin (x) - 2

4 sin^{2} (3 x) - 1 = 0

What is the general solution for 4-2sin(x)=0 ?
The general solution for 4-2sin(x)=0 is No Solution for x\in\mathbb{R}