What is the general solution for cos(θ)= 12/20 ?

The general solution for cos(θ)= 12/20 is θ=0.92729…+2pin,θ=2pi-0.92729…+2pin

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cos(θ)= 12/20

cos (θ) = \frac{12}{20}

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

Degrees

θ = 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{12}{20}

Cancel the common factor:

4

cos (θ) = \frac{3}{5}

Apply trig inverse properties

cos (θ) = \frac{3}{5}

General solutions for

cos (θ) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Show solutions in decimal form

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

\frac{1 - sin ( θ )}{3 + 3 sin ( θ )} = 1

cos (θ) = \frac{12}{15}

arctan (x) = 45

tan^{2} (x) + cot^{2} (x) - 2 = 0

12 sin (C) + 6 = 5 sin (C) + 6

What is the general solution for cos(θ)= 12/20 ?
The general solution for cos(θ)= 12/20 is θ=0.92729…+2pin,θ=2pi-0.92729…+2pin