What is the general solution for sin(x)=-1/2 sqrt(2) ?

The general solution for sin(x)=-1/2 sqrt(2) is x=(5pi)/4+2pin,x=(7pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)=-1/2 sqrt(2)

sin (x) = - \frac{1}{2} 2

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

sin (x) = - \frac{1}{2} 2

Simplify

- \frac{1}{2} 2 : - \frac{2}{2}

- \frac{1}{2} 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 2}{2}

Multiply:

1 \cdot 2 = 2

= - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

(6 cos (x) + 5 sin (x))^{2} + 11 sin^{2} (x) = 66

- 3 sin (B) - 2 = sin (B) - 2

sin (\frac{θ}{2}) = 2 - sin (\frac{θ}{2})

2 sin (x) cos (x) = cos (2 x)

(tan (x) + 1) (2 sin (x) - 1) = 0

What is the general solution for sin(x)=-1/2 sqrt(2) ?
The general solution for sin(x)=-1/2 sqrt(2) is x=(5pi)/4+2pin,x=(7pi)/4+2pin