What is the general solution for -2sin(2y)=0 ?

The general solution for -2sin(2y)=0 is y=pin,y= pi/2+pin

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-2sin(2y)=0

- 2 sin (2 y) = 0

y = πn, y = \frac{π}{2} + πn

Degrees

y = 0^{\circ} + 18 0^{\circ} n, y = 9 0^{\circ} + 18 0^{\circ} n

Solution steps

- 2 sin (2 y) = 0

Divide both sides by

- 2

- 2 sin (2 y) = 0

Divide both sides by

- 2

\frac{- 2 sin ( 2 y )}{- 2} = \frac{0}{- 2}

Simplify

sin (2 y) = 0

sin (2 y) = 0

General solutions for

sin (2 y) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 y = 0 + 2 πn, 2 y = π + 2 πn

2 y = 0 + 2 πn, 2 y = π + 2 πn

Solve

2 y = 0 + 2 πn : y = πn

2 y = 0 + 2 πn

0 + 2 πn = 2 πn

2 y = 2 πn

Divide both sides by

2

2 y = 2 πn

Divide both sides by

2

\frac{2 y}{2} = \frac{2 πn}{2}

Simplify

y = πn

y = πn

Solve

2 y = π + 2 πn : y = \frac{π}{2} + πn

2 y = π + 2 πn

Divide both sides by

2

2 y = π + 2 πn

Divide both sides by

2

\frac{2 y}{2} = \frac{π}{2} + \frac{2 πn}{2}

Simplify

y = \frac{π}{2} + πn

y = \frac{π}{2} + πn

y = πn, y = \frac{π}{2} + πn

- 3 + 4 (cos^{2} (x))^{2} + 3 sin^{2} (x) = 0

4 sin (x - 3 0^{\circ}) - 1.3 = 0

2 cos (\frac{θ}{2}) = cos (θ) + 1

cos (3 x) + sin (3 x) = 0

\frac{1}{3} = tan (x)

What is the general solution for -2sin(2y)=0 ?
The general solution for -2sin(2y)=0 is y=pin,y= pi/2+pin