What is the general solution for solvefor x,ln(y)=arctan(x)+C ?

The general solution for solvefor x,ln(y)=arctan(x)+C is x=tan(ln(y)-C)

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solvefor x,ln(y)=arctan(x)+C

solve for

x, ln (y) = arctan (x) + C

x = tan (ln (y) - C)

Solution steps

ln (y) = arctan (x) + C

Switch sides

arctan (x) + C = ln (y)

Move

C

to the right side

arctan (x) + C = ln (y)

Subtract

C

from both sides

arctan (x) + C - C = ln (y) - C

Simplify

arctan (x) = ln (y) - C

arctan (x) = ln (y) - C

Apply trig inverse properties

arctan (x) = ln (y) - C

arctan (x) = a \Rightarrow x = tan (a)

x = tan (ln (y) - C)

x = tan (ln (y) - C)

sin (x) + 2 sin (x) = 5

cos (θ) = - \frac{3}{10}

2 cos^{3} (x) = 0

50 sin (x) + 15 cos (x) = 40, 0 < x < π

x, arctan (\frac{y}{x}) = - arctan (\frac{x}{y})

What is the general solution for solvefor x,ln(y)=arctan(x)+C ?
The general solution for solvefor x,ln(y)=arctan(x)+C is x=tan(ln(y)-C)