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sin^2(x)cos^2(x)=(2-sqrt(2))/(16)

Solution

sin^{2} (x) cos^{2} (x) = \frac{2 - 2}{16}

Solution

x = 0.19634 \dots + 2 πn, x = π - 0.19634 \dots + 2 πn, x = - 0.19634 \dots + 2 πn, x = π + 0.19634 \dots + 2 πn, x = 1.37444 \dots + 2 πn, x = π - 1.37444 \dots + 2 πn, x = - 1.37444 \dots + 2 πn, x = π + 1.37444 \dots + 2 πn

Degrees

x = 11.2 5^{\circ} + 36 0^{\circ} n, x = 168.7 5^{\circ} + 36 0^{\circ} n, x = - 11.2 5^{\circ} + 36 0^{\circ} n, x = 191.2 5^{\circ} + 36 0^{\circ} n, x = 78.7 5^{\circ} + 36 0^{\circ} n, x = 101.2 5^{\circ} + 36 0^{\circ} n, x = - 78.7 5^{\circ} + 36 0^{\circ} n, x = 258.7 5^{\circ} + 36 0^{\circ} n

Solution steps

sin^{2} (x) cos^{2} (x) = \frac{2 - 2}{16}

Subtract

\frac{2 - 2}{16}

from both sides

sin^{2} (x) cos^{2} (x) - \frac{2 - 1}{8 2} = 0

Simplify

sin^{2} (x) cos^{2} (x) - \frac{2 - 1}{8 2} : \frac{8 2 sin ^{2} ( x ) cos ^{2} ( x ) - 2 + 1}{8 2}

sin^{2} (x) cos^{2} (x) - \frac{2 - 1}{8 2}

Convert element to fraction:

sin^{2} (x) cos^{2} (x) = \frac{sin ^{2} ( x ) cos ^{2} ( x ) 8 2}{8 2}

= \frac{sin ^{2} ( x ) cos ^{2} ( x ) \cdot 8 2}{8 2} - \frac{2 - 1}{8 2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ^{2} ( x ) cos ^{2} ( x ) \cdot 8 2 - ( 2 - 1 )}{8 2}

Expand

sin^{2} (x) cos^{2} (x) \cdot 82 - (2 - 1) : sin^{2} (x) cos^{2} (x) \cdot 82 - 2 + 1

sin^{2} (x) cos^{2} (x) \cdot 82 - (2 - 1)

= 82 sin^{2} (x) cos^{2} (x) - (2 - 1)

- (2 - 1) : - 2 + 1

- (2 - 1)

Distribute parentheses

= - (2) - (- 1)

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - 2 + 1

= sin^{2} (x) cos^{2} (x) \cdot 82 - 2 + 1

= \frac{8 2 sin ^{2} ( x ) cos ^{2} ( x ) - 2 + 1}{8 2}

\frac{8 2 sin ^{2} ( x ) cos ^{2} ( x ) - 2 + 1}{8 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

82 sin^{2} (x) cos^{2} (x) - 2 + 1 = 0

Rewrite using trig identities

1 - 2 + 8 cos^{2} (x) sin^{2} (x) 2

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= 1 - 2 + 8 (1 - sin^{2} (x)) sin^{2} (x) 2

1 - 2 + (1 - sin^{2} (x)) \cdot 8 sin^{2} (x) 2 = 0

Solve by substitution

1 - 2 + (1 - sin^{2} (x)) \cdot 8 sin^{2} (x) 2 = 0

Let:

sin (x) = u

1 - 2 + (1 - u^{2}) \cdot 8 u^{2} 2 = 0

1 - 2 + (1 - u^{2}) \cdot 8 u^{2} 2 = 0 : u = \frac{2 - 2 64 + 32 2 + 16}{8}, u = - \frac{2 - 2 64 + 32 2 + 16}{8}, u = \frac{2 2 64 + 32 2 + 16}{8}, u = - \frac{2 2 64 + 32 2 + 16}{8}

1 - 2 + (1 - u^{2}) \cdot 8 u^{2} 2 = 0

Expand

1 - 2 + (1 - u^{2}) \cdot 8 u^{2} 2 : 1 - 2 + 82 u^{2} - 82 u^{4}

1 - 2 + (1 - u^{2}) \cdot 8 u^{2} 2

= 1 - 2 + 82 u^{2} (1 - u^{2})

Expand

8 u^{2} 2 (1 - u^{2}) : 82 u^{2} - 82 u^{4}

8 u^{2} 2 (1 - u^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = 8 u^{2} 2, b = 1, c = u^{2}

= 8 u^{2} 2 \cdot 1 - 8 u^{2} 2 u^{2}

= 8 \cdot 1 \cdot 2 u^{2} - 82 u^{2} u^{2}

Simplify

8 \cdot 1 \cdot 2 u^{2} - 82 u^{2} u^{2} : 82 u^{2} - 82 u^{4}

8 \cdot 1 \cdot 2 u^{2} - 82 u^{2} u^{2}

8 \cdot 1 \cdot 2 u^{2} = 82 u^{2}

8 \cdot 1 \cdot 2 u^{2}

Multiply the numbers:

8 \cdot 1 = 8

= 82 u^{2}

82 u^{2} u^{2} = 82 u^{4}

82 u^{2} u^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u^{2} = u^{2 + 2}

= 82 u^{2 + 2}

Add the numbers:

2 + 2 = 4

= 82 u^{4}

= 82 u^{2} - 82 u^{4}

= 82 u^{2} - 82 u^{4}

= 1 - 2 + 82 u^{2} - 82 u^{4}

1 - 2 + 82 u^{2} - 82 u^{4} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- 82 u^{4} + 82 u^{2} + 1 - 2 = 0

Rewrite the equation with

v = u^{2}

and

v^{2} = u^{4}

- 82 v^{2} + 82 v + 1 - 2 = 0

Solve

- 82 v^{2} + 82 v + 1 - 2 = 0 : v = \frac{- 2 64 + 32 2 + 16}{32}, v = \frac{2 64 + 32 2 + 16}{32}

- 82 v^{2} + 82 v + 1 - 2 = 0

Solve with the quadratic formula

- 82 v^{2} + 82 v + 1 - 2 = 0

Quadratic Equation Formula:

For

a = - 82, b = 82, c = 1 - 2

v_{1, 2} = \frac{- 8 2 \pm ( 8 2 ) ^{2} - 4 ( - 8 2 ) ( 1 - 2 )}{2 ( - 8 2 )}

v_{1, 2} = \frac{- 8 2 \pm ( 8 2 ) ^{2} - 4 ( - 8 2 ) ( 1 - 2 )}{2 ( - 8 2 )}

(82)^{2} - 4 (- 82) (1 - 2) = 64 + 322

(82)^{2} - 4 (- 82) (1 - 2)

Apply rule

- (- a) = a

= (82)^{2} + 4 \cdot 82 (1 - 2)

(82)^{2} = 8^{2} \cdot 2

(82)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 8^{2} (2)^{2}

(2)^{2} : 2

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 2

= 8^{2} \cdot 2

4 \cdot 82 (1 - 2) = 322 (1 - 2)

4 \cdot 82 (1 - 2)

Multiply the numbers:

4 \cdot 8 = 32

= 322 (1 - 2)

= 8^{2} \cdot 2 + 322 (1 - 2)

8^{2} \cdot 2 = 128

8^{2} \cdot 2

8^{2} = 64

= 64 \cdot 2

Multiply the numbers:

64 \cdot 2 = 128

= 128

= 128 + 322 (1 - 2)

Expand

128 + 322 (1 - 2) : 64 + 322

128 + 322 (1 - 2)

Expand

322 (1 - 2) : 322 - 64

322 (1 - 2)

Apply the distributive law:

a (b - c) = ab - a c

a = 322, b = 1, c = 2

= 322 \cdot 1 - 3222

= 32 \cdot 1 \cdot 2 - 3222

Simplify

32 \cdot 1 \cdot 2 - 3222 : 322 - 64

32 \cdot 1 \cdot 2 - 3222

32 \cdot 1 \cdot 2 = 322

32 \cdot 1 \cdot 2

Multiply the numbers:

32 \cdot 1 = 32

= 322

3222 = 64

3222

Apply radical rule:

a a = a

22 = 2

= 32 \cdot 2

Multiply the numbers:

32 \cdot 2 = 64

= 64

= 322 - 64

= 322 - 64

= 128 + 322 - 64

Subtract the numbers:

128 - 64 = 64

= 64 + 322

= 64 + 322

v_{1, 2} = \frac{- 8 2 \pm 64 + 32 2}{2 ( - 8 2 )}

Separate the solutions

v_{1} = \frac{- 8 2 + 64 + 32 2}{2 ( - 8 2 )}, v_{2} = \frac{- 8 2 - 64 + 32 2}{2 ( - 8 2 )}

v = \frac{- 8 2 + 64 + 32 2}{2 ( - 8 2 )} : \frac{- 2 64 + 32 2 + 16}{32}

\frac{- 8 2 + 64 + 32 2}{2 ( - 8 2 )}

Remove parentheses:

(- a) = - a

= \frac{- 8 2 + 64 + 32 2}{- 2 \cdot 8 2}

Multiply the numbers:

2 \cdot 8 = 16

= \frac{- 8 2 + 64 + 32 2}{- 16 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

- 82 + 64 + 322 = - (- 64 + 322 + 82)

= \frac{- 64 + 32 2 + 8 2}{16 2}

Rationalize

\frac{- 64 + 32 2 + 8 2}{16 2} : \frac{- 2 64 + 32 2 + 16}{32}

\frac{- 64 + 32 2 + 8 2}{16 2}

Multiply by the conjugate

\frac{2}{2}

= \frac{( - 64 + 32 2 + 8 2 ) 2}{16 2 2}

(- 64 + 322 + 82) 2 = - 2 64 + 322 + 16

(- 64 + 322 + 82) 2

= 2 (- 64 + 322 + 82)

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = - 64 + 322, c = 82

= 2 (- 64 + 322) + 2 \cdot 82

Apply minus-plus rules

+ (- a) = - a

= - 2 64 + 322 + 822

822 = 16

822

Apply radical rule:

a a = a

22 = 2

= 8 \cdot 2

Multiply the numbers:

8 \cdot 2 = 16

= 16

= - 2 64 + 322 + 16

1622 = 32

1622

Apply radical rule:

a a = a

22 = 2

= 16 \cdot 2

Multiply the numbers:

16 \cdot 2 = 32

= 32

= \frac{- 2 64 + 32 2 + 16}{32}

= \frac{- 2 64 + 32 2 + 16}{32}

v = \frac{- 8 2 - 64 + 32 2}{2 ( - 8 2 )} : \frac{2 64 + 32 2 + 16}{32}

\frac{- 8 2 - 64 + 32 2}{2 ( - 8 2 )}

Remove parentheses:

(- a) = - a

= \frac{- 8 2 - 64 + 32 2}{- 2 \cdot 8 2}

Multiply the numbers:

2 \cdot 8 = 16

= \frac{- 8 2 - 64 + 32 2}{- 16 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

- 82 - 64 + 322 = - (64 + 322 + 82)

= \frac{64 + 32 2 + 8 2}{16 2}

Rationalize

\frac{64 + 32 2 + 8 2}{16 2} : \frac{2 64 + 32 2 + 16}{32}

\frac{64 + 32 2 + 8 2}{16 2}

Multiply by the conjugate

\frac{2}{2}

= \frac{( 64 + 32 2 + 8 2 ) 2}{16 2 2}

(64 + 322 + 82) 2 = 2 64 + 322 + 16

(64 + 322 + 82) 2

= 2 (64 + 322 + 82)

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = 64 + 322, c = 82

= 2 64 + 322 + 2 \cdot 82

= 2 64 + 322 + 822

822 = 16

822

Apply radical rule:

a a = a

22 = 2

= 8 \cdot 2

Multiply the numbers:

8 \cdot 2 = 16

= 16

= 2 64 + 322 + 16

1622 = 32

1622

Apply radical rule:

a a = a

22 = 2

= 16 \cdot 2

Multiply the numbers:

16 \cdot 2 = 32

= 32

= \frac{2 64 + 32 2 + 16}{32}

= \frac{2 64 + 32 2 + 16}{32}

The solutions to the quadratic equation are:

v = \frac{- 2 64 + 32 2 + 16}{32}, v = \frac{2 64 + 32 2 + 16}{32}

v = \frac{- 2 64 + 32 2 + 16}{32}, v = \frac{2 64 + 32 2 + 16}{32}

Substitute back

v = u^{2},

solve for

u

Solve

u^{2} = \frac{- 2 64 + 32 2 + 16}{32} : u = \frac{2 - 2 64 + 32 2 + 16}{8}, u = - \frac{2 - 2 64 + 32 2 + 16}{8}

u^{2} = \frac{- 2 64 + 32 2 + 16}{32}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{- 2 64 + 32 2 + 16}{32}, u = - \frac{- 2 64 + 32 2 + 16}{32}

\frac{- 2 64 + 32 2 + 16}{32} = \frac{2 - 2 64 + 32 2 + 16}{8}

\frac{- 2 64 + 32 2 + 16}{32}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{- 2 64 + 32 2 + 16}{32}

32 = 42

32

Prime factorization of

32 : 2^{5}

32

32

divides by

232 = 16 \cdot 2

= 2 \cdot 16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

= 2^{5}

= 2^{5}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

= 2^{4} \cdot 2

Apply radical rule:

= 2 2^{4}

Apply radical rule:

2^{4} = 2^{\frac{4}{2}} = 2^{2}

= 2^{2} 2

Refine

= 42

= \frac{- 2 64 + 32 2 + 16}{4 2}

Rationalize

\frac{- 2 64 + 32 2 + 16}{4 2} : \frac{2 - 2 64 + 32 2 + 16}{8}

\frac{- 2 64 + 32 2 + 16}{4 2}

Multiply by the conjugate

\frac{2}{2}

= \frac{- 2 64 + 32 2 + 16 2}{4 2 2}

422 = 8

422

Apply radical rule:

a a = a

22 = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= \frac{2 - 2 64 + 32 2 + 16}{8}

= \frac{2 - 2 64 + 32 2 + 16}{8}

- \frac{- 2 64 + 32 2 + 16}{32} = - \frac{2 - 2 64 + 32 2 + 16}{8}

- \frac{- 2 64 + 32 2 + 16}{32}

Simplify

\frac{- 2 64 + 32 2 + 16}{32} : \frac{- 2 64 + 32 2 + 16}{4 2}

\frac{- 2 64 + 32 2 + 16}{32}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{- 2 64 + 32 2 + 16}{32}

32 = 42

32

Prime factorization of

32 : 2^{5}

32

32

divides by

232 = 16 \cdot 2

= 2 \cdot 16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

= 2^{5}

= 2^{5}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

= 2^{4} \cdot 2

Apply radical rule:

= 2 2^{4}

Apply radical rule:

2^{4} = 2^{\frac{4}{2}} = 2^{2}

= 2^{2} 2

Refine

= 42

= \frac{- 2 64 + 32 2 + 16}{4 2}

= - \frac{- 2 64 + 32 2 + 16}{4 2}

Rationalize

- \frac{- 2 64 + 32 2 + 16}{4 2} : - \frac{2 - 2 64 + 32 2 + 16}{8}

- \frac{- 2 64 + 32 2 + 16}{4 2}

Multiply by the conjugate

\frac{2}{2}

= - \frac{- 2 64 + 32 2 + 16 2}{4 2 2}

422 = 8

422

Apply radical rule:

a a = a

22 = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= - \frac{2 - 2 64 + 32 2 + 16}{8}

= - \frac{2 - 2 64 + 32 2 + 16}{8}

u = \frac{2 - 2 64 + 32 2 + 16}{8}, u = - \frac{2 - 2 64 + 32 2 + 16}{8}

Solve

u^{2} = \frac{2 64 + 32 2 + 16}{32} : u = \frac{2 2 64 + 32 2 + 16}{8}, u = - \frac{2 2 64 + 32 2 + 16}{8}

u^{2} = \frac{2 64 + 32 2 + 16}{32}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = \frac{2 64 + 32 2 + 16}{32}, u = - \frac{2 64 + 32 2 + 16}{32}

\frac{2 64 + 32 2 + 16}{32} = \frac{2 2 64 + 32 2 + 16}{8}

\frac{2 64 + 32 2 + 16}{32}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{2 64 + 32 2 + 16}{32}

32 = 42

32

Prime factorization of

32 : 2^{5}

32

32

divides by

232 = 16 \cdot 2

= 2 \cdot 16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

= 2^{5}

= 2^{5}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

= 2^{4} \cdot 2

Apply radical rule:

= 2 2^{4}

Apply radical rule:

2^{4} = 2^{\frac{4}{2}} = 2^{2}

= 2^{2} 2

Refine

= 42

= \frac{2 64 + 32 2 + 16}{4 2}

Rationalize

\frac{2 64 + 32 2 + 16}{4 2} : \frac{2 2 64 + 32 2 + 16}{8}

\frac{2 64 + 32 2 + 16}{4 2}

Multiply by the conjugate

\frac{2}{2}

= \frac{2 64 + 32 2 + 16 2}{4 2 2}

422 = 8

422

Apply radical rule:

a a = a

22 = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= \frac{2 2 64 + 32 2 + 16}{8}

= \frac{2 2 64 + 32 2 + 16}{8}

- \frac{2 64 + 32 2 + 16}{32} = - \frac{2 2 64 + 32 2 + 16}{8}

- \frac{2 64 + 32 2 + 16}{32}

Simplify

\frac{2 64 + 32 2 + 16}{32} : \frac{2 64 + 32 2 + 16}{4 2}

\frac{2 64 + 32 2 + 16}{32}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{2 64 + 32 2 + 16}{32}

32 = 42

32

Prime factorization of

32 : 2^{5}

32

32

divides by

232 = 16 \cdot 2

= 2 \cdot 16

16

divides by

216 = 8 \cdot 2

= 2 \cdot 2 \cdot 8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

2

is a prime number, therefore no further factorization is possible

= 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2

= 2^{5}

= 2^{5}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

= 2^{4} \cdot 2

Apply radical rule:

= 2 2^{4}

Apply radical rule:

2^{4} = 2^{\frac{4}{2}} = 2^{2}

= 2^{2} 2

Refine

= 42

= \frac{2 64 + 32 2 + 16}{4 2}

= - \frac{2 64 + 32 2 + 16}{4 2}

Rationalize

- \frac{2 64 + 32 2 + 16}{4 2} : - \frac{2 2 64 + 32 2 + 16}{8}

- \frac{2 64 + 32 2 + 16}{4 2}

Multiply by the conjugate

\frac{2}{2}

= - \frac{2 64 + 32 2 + 16 2}{4 2 2}

422 = 8

422

Apply radical rule:

a a = a

22 = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= - \frac{2 2 64 + 32 2 + 16}{8}

= - \frac{2 2 64 + 32 2 + 16}{8}

u = \frac{2 2 64 + 32 2 + 16}{8}, u = - \frac{2 2 64 + 32 2 + 16}{8}

The solutions are

u = \frac{2 - 2 64 + 32 2 + 16}{8}, u = - \frac{2 - 2 64 + 32 2 + 16}{8}, u = \frac{2 2 64 + 32 2 + 16}{8}, u = - \frac{2 2 64 + 32 2 + 16}{8}

Substitute back

u = sin (x)

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8}, sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8}, sin (x) = \frac{2 2 64 + 32 2 + 16}{8}, sin (x) = - \frac{2 2 64 + 32 2 + 16}{8}

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8}, sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8}, sin (x) = \frac{2 2 64 + 32 2 + 16}{8}, sin (x) = - \frac{2 2 64 + 32 2 + 16}{8}

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8} : x = arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8}

Apply trig inverse properties

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8}

General solutions for

sin (x) = \frac{2 - 2 64 + 32 2 + 16}{8}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

x = arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8} : x = arcsin - \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8}

Apply trig inverse properties

sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8}

General solutions for

sin (x) = - \frac{2 - 2 64 + 32 2 + 16}{8}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin - \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

x = arcsin - \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = \frac{2 2 64 + 32 2 + 16}{8} : x = arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = \frac{2 2 64 + 32 2 + 16}{8}

Apply trig inverse properties

sin (x) = \frac{2 2 64 + 32 2 + 16}{8}

General solutions for

sin (x) = \frac{2 2 64 + 32 2 + 16}{8}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

x = arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = - \frac{2 2 64 + 32 2 + 16}{8} : x = arcsin - \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

sin (x) = - \frac{2 2 64 + 32 2 + 16}{8}

Apply trig inverse properties

sin (x) = - \frac{2 2 64 + 32 2 + 16}{8}

General solutions for

sin (x) = - \frac{2 2 64 + 32 2 + 16}{8}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin - \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

x = arcsin - \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

Combine all the solutions

x = arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = arcsin - \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 - 2 64 + 32 2 + 16}{8} + 2 πn, x = arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π - arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = arcsin - \frac{2 2 64 + 32 2 + 16}{8} + 2 πn, x = π + arcsin \frac{2 2 64 + 32 2 + 16}{8} + 2 πn

Show solutions in decimal form

x = 0.19634 \dots + 2 πn, x = π - 0.19634 \dots + 2 πn, x = - 0.19634 \dots + 2 πn, x = π + 0.19634 \dots + 2 πn, x = 1.37444 \dots + 2 πn, x = π - 1.37444 \dots + 2 πn, x = - 1.37444 \dots + 2 πn, x = π + 1.37444 \dots + 2 πn

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