What is the value of (sin(60))^2+(cos(60))^2 ?

The value of (sin(60))^2+(cos(60))^2 is 1

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(sin(60))^2+(cos(60))^2

(sin (6 0^{\circ}))^{2} + (cos (6 0^{\circ}))^{2}

1

Solution steps

(sin (6 0^{\circ}))^{2} + (cos (6 0^{\circ}))^{2}

= sin^{2} (6 0^{\circ}) + cos^{2} (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

= (\frac{3}{2})^{2} + (\frac{1}{2})^{2}

Simplify

(\frac{3}{2})^{2} + (\frac{1}{2})^{2} : 1

= 1

arcsinh (5)

arcsinh (2)

5 cos^{2} (0)

\frac{1 - cos ( 0.1 )}{0.1}

- sin (12 0^{\circ})

What is the value of (sin(60))^2+(cos(60))^2 ?
The value of (sin(60))^2+(cos(60))^2 is 1