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人気のある三角関数 >

tan^2(45+x/3)=0.58

解

tan^{2} (4 5^{\circ} + \frac{x}{3}) = 0.58

解

x = 3 \cdot 0.65086 \dots + 54 0^{\circ} n - 13 5^{\circ}, x = - 3 \cdot 0.65086 \dots + 54 0^{\circ} n - 13 5^{\circ}

+1

ラジアン

x = 3 \cdot 0.65086 \dots - \frac{3 π}{4} + 3 πn, x = - 3 \cdot 0.65086 \dots - \frac{3 π}{4} + 3 πn

解答ステップ

tan^{2} (4 5^{\circ} + \frac{x}{3}) = 0.58

置換で解く

tan^{2} (4 5^{\circ} + \frac{x}{3}) = 0.58

仮定:

tan (4 5^{\circ} + \frac{x}{3}) = u

u^{2} = 0.58

u^{2} = 0.58 : u = 0.58, u = - 0.58

u^{2} = 0.58

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = 0.58, u = - 0.58

代用を戻す

u = tan (4 5^{\circ} + \frac{x}{3})

tan (4 5^{\circ} + \frac{x}{3}) = 0.58, tan (4 5^{\circ} + \frac{x}{3}) = - 0.58

tan (4 5^{\circ} + \frac{x}{3}) = 0.58, tan (4 5^{\circ} + \frac{x}{3}) = - 0.58

tan (4 5^{\circ} + \frac{x}{3}) = 0.58 : x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

三角関数の逆数プロパティを適用する

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

以下の一般解

tan (4 5^{\circ} + \frac{x}{3}) = 0.58

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

解く

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n : x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

4 5^{\circ}

を右側に移動します

4 5^{\circ} + \frac{x}{3} = arctan (0.58) + 18 0^{\circ} n

両辺から

4 5^{\circ}

を引く

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

簡素化

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

以下で両辺を乗じる:

3

\frac{x}{3} = arctan (0.58) + 18 0^{\circ} n - 4 5^{\circ}

以下で両辺を乗じる:

3

\frac{3 x}{3} = 3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

\frac{3 x}{3} = 3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

\frac{3 x}{3} : x

\frac{3 x}{3}

数を割る:

\frac{3}{3} = 1

= x

簡素化

3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ} : 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

3 arctan (0.58) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

乗じる

3 \cdot 4 5^{\circ} : 13 5^{\circ}

3 \cdot 4 5^{\circ}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 13 5^{\circ}

= 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}

tan (4 5^{\circ} + \frac{x}{3}) = - 0.58 : x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

tan (4 5^{\circ} + \frac{x}{3}) = - 0.58

三角関数の逆数プロパティを適用する

tan (4 5^{\circ} + \frac{x}{3}) = - 0.58

以下の一般解

tan (4 5^{\circ} + \frac{x}{3}) = - 0.58

tan (x) = - a \Rightarrow x = arctan (- a) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (- 0.58) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = arctan (- 0.58) + 18 0^{\circ} n

解く

4 5^{\circ} + \frac{x}{3} = arctan (- 0.58) + 18 0^{\circ} n : x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

4 5^{\circ} + \frac{x}{3} = arctan (- 0.58) + 18 0^{\circ} n

簡素化

arctan (- 0.58) + 18 0^{\circ} n : - arctan (\frac{29}{5 2}) + 18 0^{\circ} n

arctan (- 0.58) + 18 0^{\circ} n

arctan (- 0.58) = - arctan (\frac{58}{10})

arctan (- 0.58)

= arctan (- \frac{29}{50})

次のプロパティを使用する:

arctan (- x) = - arctan (x)

arctan (- \frac{29}{50}) = - arctan (\frac{29}{50})

= - arctan (\frac{29}{50})

= - arctan (\frac{58}{10})

= - arctan (\frac{58}{10}) + 18 0^{\circ} n

\frac{58}{10} = \frac{29}{5 2}

\frac{58}{10}

因数

58 : 229

因数

58 = 2 \cdot 29

= 2 \cdot 29

累乗根の規則を適用する:

n ab = n a n b

= 229

因数

10 : 2 \cdot 5

因数

10 = 2 \cdot 5

= \frac{2 29}{2 \cdot 5}

キャンセル

\frac{2 29}{2 \cdot 5} : \frac{29}{2 \cdot 5}

\frac{2 29}{2 \cdot 5}

累乗根の規則を適用する:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2 ^{\frac{1}{2}} 29}{2 \cdot 5}

指数の規則を適用する:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{29}{5 \cdot 2 ^{- \frac{1}{2} + 1}}

数を引く:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{29}{5 \cdot 2 ^{\frac{1}{2}}}

累乗根の規則を適用する:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= \frac{29}{5 2}

= \frac{29}{2 \cdot 5}

= - arctan (\frac{29}{5 2}) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{3} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n

4 5^{\circ}

を右側に移動します

4 5^{\circ} + \frac{x}{3} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n

両辺から

4 5^{\circ}

を引く

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

簡素化

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

簡素化

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ} : \frac{x}{3}

4 5^{\circ} + \frac{x}{3} - 4 5^{\circ}

類似した元を足す:

4 5^{\circ} - 4 5^{\circ} = 0

= \frac{x}{3}

簡素化

- arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ} : - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

- arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

= - arctan (\frac{58}{10}) + 18 0^{\circ} n - 4 5^{\circ}

\frac{58}{10} = \frac{29}{5 2}

\frac{58}{10}

因数

58 : 229

因数

58 = 2 \cdot 29

= 2 \cdot 29

累乗根の規則を適用する:

n ab = n a n b

= 229

因数

10 : 2 \cdot 5

因数

10 = 2 \cdot 5

= \frac{2 29}{2 \cdot 5}

キャンセル

\frac{2 29}{2 \cdot 5} : \frac{29}{2 \cdot 5}

\frac{2 29}{2 \cdot 5}

累乗根の規則を適用する:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2 ^{\frac{1}{2}} 29}{2 \cdot 5}

指数の規則を適用する:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{29}{5 \cdot 2 ^{- \frac{1}{2} + 1}}

数を引く:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{29}{5 \cdot 2 ^{\frac{1}{2}}}

累乗根の規則を適用する:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= \frac{29}{5 2}

= \frac{29}{2 \cdot 5}

= - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

さらに簡約できない

= - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{3} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{3} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{3} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

以下で両辺を乗じる:

3

\frac{x}{3} = - arctan (\frac{29}{5 2}) + 18 0^{\circ} n - 4 5^{\circ}

以下で両辺を乗じる:

3

\frac{3 x}{3} = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

\frac{3 x}{3} = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

\frac{3 x}{3} : x

\frac{3 x}{3}

数を割る:

\frac{3}{3} = 1

= x

簡素化

- 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ} : - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

- 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

簡素化

arctan (\frac{29}{5 2}) : arctan (\frac{58}{10})

arctan (\frac{29}{5 2})

= arctan (\frac{58}{10})

= - 3 arctan (\frac{58}{10}) + 54 0^{\circ} n - 3 \cdot 4 5^{\circ}

乗じる

3 \cdot 4 5^{\circ} : 13 5^{\circ}

3 \cdot 4 5^{\circ}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 13 5^{\circ}

= - 3 arctan (\frac{58}{10}) + 54 0^{\circ} n - 13 5^{\circ}

\frac{58}{10} = \frac{29}{5 2}

\frac{58}{10}

因数

58 : 229

因数

58 = 2 \cdot 29

= 2 \cdot 29

累乗根の規則を適用する:

n ab = n a n b

= 229

因数

10 : 2 \cdot 5

因数

10 = 2 \cdot 5

= \frac{2 29}{2 \cdot 5}

キャンセル

\frac{2 29}{2 \cdot 5} : \frac{29}{2 \cdot 5}

\frac{2 29}{2 \cdot 5}

累乗根の規則を適用する:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2 ^{\frac{1}{2}} 29}{2 \cdot 5}

指数の規則を適用する:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{29}{5 \cdot 2 ^{- \frac{1}{2} + 1}}

数を引く:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{29}{5 \cdot 2 ^{\frac{1}{2}}}

累乗根の規則を適用する:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= \frac{29}{5 2}

= \frac{29}{2 \cdot 5}

= - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

すべての解を組み合わせる

x = 3 arctan (0.58) + 54 0^{\circ} n - 13 5^{\circ}, x = - 3 arctan (\frac{29}{5 2}) + 54 0^{\circ} n - 13 5^{\circ}

10進法形式で解を証明する

x = 3 \cdot 0.65086 \dots + 54 0^{\circ} n - 13 5^{\circ}, x = - 3 \cdot 0.65086 \dots + 54 0^{\circ} n - 13 5^{\circ}

グラフ

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