What is the general solution for 1=4tan(-4/81+c) ?

The general solution for 1=4tan(-4/81+c) is c=0.24497…+pin+4/81

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1=4tan(-4/81+c)

1 = 4 tan (- \frac{4}{81} + c)

c = 0.24497 \dots + πn + \frac{4}{81}

Degrees

c = 16.86566 \dots^{\circ} + 18 0^{\circ} n

Solution steps

1 = 4 tan (- \frac{4}{81} + c)

Switch sides

4 tan (- \frac{4}{81} + c) = 1

Divide both sides by

4

4 tan (- \frac{4}{81} + c) = 1

Divide both sides by

4

\frac{4 tan ( - \frac{4}{81} + c )}{4} = \frac{1}{4}

Simplify

tan (- \frac{4}{81} + c) = \frac{1}{4}

tan (- \frac{4}{81} + c) = \frac{1}{4}

Apply trig inverse properties

tan (- \frac{4}{81} + c) = \frac{1}{4}

General solutions for

tan (- \frac{4}{81} + c) = \frac{1}{4}

tan (x) = a \Rightarrow x = arctan (a) + πn

- \frac{4}{81} + c = arctan (\frac{1}{4}) + πn

- \frac{4}{81} + c = arctan (\frac{1}{4}) + πn

Solve

- \frac{4}{81} + c = arctan (\frac{1}{4}) + πn : c = arctan (\frac{1}{4}) + πn + \frac{4}{81}

- \frac{4}{81} + c = arctan (\frac{1}{4}) + πn

Move

\frac{4}{81}

to the right side

- \frac{4}{81} + c = arctan (\frac{1}{4}) + πn

Add

\frac{4}{81}

to both sides

- \frac{4}{81} + c + \frac{4}{81} = arctan (\frac{1}{4}) + πn + \frac{4}{81}

Simplify

c = arctan (\frac{1}{4}) + πn + \frac{4}{81}

c = arctan (\frac{1}{4}) + πn + \frac{4}{81}

c = arctan (\frac{1}{4}) + πn + \frac{4}{81}

Show solutions in decimal form

c = 0.24497 \dots + πn + \frac{4}{81}

15 cos^{2} (x) + 7 cos (x) - 2 = 0

2 (sin (t))^{2} - sin (t) - 1 = 0

cos (x) = 0.625

0 = 2 cos (t)

sin (z) \cdot cos (z) = 1

What is the general solution for 1=4tan(-4/81+c) ?
The general solution for 1=4tan(-4/81+c) is c=0.24497…+pin+4/81