What is the general solution for 0=2cos(t) ?

The general solution for 0=2cos(t) is t= pi/2+2pin,t=(3pi)/2+2pin

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0=2cos(t)

0 = 2 cos (t)

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

0 = 2 cos (t)

Switch sides

2 cos (t) = 0

Divide both sides by

2

2 cos (t) = 0

Divide both sides by

2

\frac{2 cos ( t )}{2} = \frac{0}{2}

Simplify

cos (t) = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

sin (z) \cdot cos (z) = 1

0 = 2 cos (x)

\frac{cos ( x )}{cos ( x )} = \frac{cos ( x )}{1 + sin ( x )}

- 2 cos (θ) - 3 = 0

4 cos^{2} (2 x) = 1

What is the general solution for 0=2cos(t) ?
The general solution for 0=2cos(t) is t= pi/2+2pin,t=(3pi)/2+2pin