What is the general solution for sec(x)=1,-2pi<= x<= 2pi ?

The general solution for sec(x)=1,-2pi<= x<= 2pi is x=0,x=2pi,x=-2pi

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sec(x)=1,-2pi<= x<= 2pi

sec (x) = 1, - 2 π \leq x \leq 2 π

x = 0, x = 2 π, x = - 2 π

Degrees

x = 0^{\circ}, x = 36 0^{\circ}, x = - 36 0^{\circ}

Solution steps

sec (x) = 1, - 2 π \leq x \leq 2 π

General solutions for

sec (x) = 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

Solutions for the range

- 2 π \leq x \leq 2 π

x = 0, x = 2 π, x = - 2 π

tan (t) = \frac{4}{3}, sin (t)

cos (x) = \frac{2}{6}

16 sin^{2} (x) = 9

tan (x) - cos (x) = 0

- 8 \cdot sin (0.784 + x) = 0

What is the general solution for sec(x)=1,-2pi<= x<= 2pi ?
The general solution for sec(x)=1,-2pi<= x<= 2pi is x=0,x=2pi,x=-2pi