What is the general solution for sin(θ)=0.9848,0<= θ<360 ?

The general solution for sin(θ)=0.9848,0<= θ<360 is θ=1.39621…,θ=180-1.39621…

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sin(θ)=0.9848,0<= θ<360

sin (θ) = 0.9848, 0^{\circ} \leq θ < 36 0^{\circ}

θ = 1.39621 \dots, θ = 18 0^{\circ} - 1.39621 \dots

Radians

θ = 1.39621 \dots, θ = π - 1.39621 \dots

Solution steps

sin (θ) = 0.9848, 0^{\circ} \leq θ < 36 0^{\circ}

Apply trig inverse properties

sin (θ) = 0.9848

General solutions for

sin (θ) = 0.9848

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (0.9848) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (0.9848) + 36 0^{\circ} n

θ = arcsin (0.9848) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (0.9848) + 36 0^{\circ} n

Solutions for the range

0 \leq θ < 36 0^{\circ}

θ = 1.39621 \dots, θ = 18 0^{\circ} - 1.39621 \dots

sin^{2} (x) = \frac{( 7 m - 9 )}{9}

sin (x) = 2, 0 < x < 2 π

2 csc^{2} (x) - 2 csc (x) - 1 = 0

sin (x) - cos (x) = \frac{1}{2}

cos (x) = \frac{6}{15}

What is the general solution for sin(θ)=0.9848,0<= θ<360 ?
The general solution for sin(θ)=0.9848,0<= θ<360 is θ=1.39621…,θ=180-1.39621…