{
"query": {
"display": "$$\\tan\\left(\\frac{x}{2}\\right)=\\sqrt{3},\\:0\\le\\:x<2π$$",
"symbolab_question": "EQUATION#\\tan(\\frac{x}{2})=\\sqrt{3},0\\le x<2π"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=\\frac{2π}{3}",
"degrees": "x=120^{\\circ }",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\tan\\left(\\frac{x}{2}\\right)=\\sqrt{3},\\:0\\le\\:x<2π{\\quad:\\quad}x=\\frac{2π}{3}$$",
"input": "\\tan\\left(\\frac{x}{2}\\right)=\\sqrt{3},\\:0\\le\\:x<2π",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\tan\\left(\\frac{x}{2}\\right)=\\sqrt{3}$$",
"result": "\\frac{x}{2}=\\frac{π}{3}+πn",
"steps": [
{
"type": "step",
"primary": "$$\\tan\\left(x\\right)$$ periodicity table with $$πn$$ cycle:<br/>$$\\begin{array}{|c|c|}\\hline x&\\tan(x)\\\\\\hline 0&0\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{3}\\\\\\hline \\frac{π}{4}&1\\\\\\hline \\frac{π}{3}&\\sqrt{3}\\\\\\hline \\frac{π}{2}&\\pm\\infty\\\\\\hline \\frac{2π}{3}&-\\sqrt{3}\\\\\\hline \\frac{3π}{4}&-1\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{3}\\\\\\hline &\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "\\frac{x}{2}=\\frac{π}{3}+πn"
}
],
"meta": {
"interimType": "Trig General Solutions tan 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$\\frac{x}{2}=\\frac{π}{3}+πn:{\\quad}x=\\frac{2π}{3}+2πn$$",
"input": "\\frac{x}{2}=\\frac{π}{3}+πn",
"steps": [
{
"type": "interim",
"title": "Multiply both sides by $$2$$",
"input": "\\frac{x}{2}=\\frac{π}{3}+πn",
"result": "x=\\frac{2π}{3}+2πn",
"steps": [
{
"type": "step",
"primary": "Multiply both sides by $$2$$",
"result": "\\frac{2x}{2}=2\\cdot\\:\\frac{π}{3}+2πn"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{2x}{2}=2\\cdot\\:\\frac{π}{3}+2πn",
"result": "x=\\frac{2π}{3}+2πn",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{2x}{2}:{\\quad}x$$",
"input": "\\frac{2x}{2}",
"steps": [
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=x"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7wyZUoCmW9j1Yiq04nFm+Ei061ljBSPJeENOw2efoSWt2cZ6LAXMcKee6PSyjLEFrRSpN33oxZMojoqvYhvSJACLkpiVA7S8UT8ieezZKu6rogJeWDMKCUBljFmQOLy/H"
}
},
{
"type": "interim",
"title": "Simplify $$2\\cdot\\:\\frac{π}{3}+2πn:{\\quad}\\frac{2π}{3}+2πn$$",
"input": "2\\cdot\\:\\frac{π}{3}+2πn",
"steps": [
{
"type": "interim",
"title": "Multiply $$2\\cdot\\:\\frac{π}{3}\\::{\\quad}\\frac{2π}{3}$$",
"input": "2\\cdot\\:\\frac{π}{3}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{π2}{3}"
}
],
"meta": {
"interimType": "Generic Multiply Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{2π}{3}+2πn"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7/OsC643lXZbU+VEjF1qvihKvBpaUh7KoJ5CHcKUNwB0gJ/ZZA32ZInFBpDtxBfiKXYGCmiBF99lesmXZ9iIfJ3Dp+bJB1yvfuIMe/mO4CCvvbBmbuQNTF0TphKZ8RuvatFeoIslXtlqmFYFR1OwmZBwvBbPxb16b5MJzsWVCT2PiwcvEzvOwRqXrYyQY5dyC"
}
},
{
"type": "step",
"result": "x=\\frac{2π}{3}+2πn"
}
],
"meta": {
"interimType": "Generic Simplify 0Eq"
}
}
],
"meta": {
"interimType": "Multiply Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "x=\\frac{2π}{3}+2πn"
},
{
"type": "step",
"primary": "Solutions for the range $$0\\le\\:x<2π$$",
"result": "x=\\frac{2π}{3}"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "\\tan(\\frac{x}{2})-\\sqrt{3},0\\le x<2π"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
General solutions for
periodicity table with cycle:
Solve
Multiply both sides by
Multiply both sides by
Simplify
Simplify
Divide the numbers:
Simplify
Multiply
Multiply fractions:
Solutions for the range
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the general solution for tan(x/2)=sqrt(3),0<= x<2pi ?
The general solution for tan(x/2)=sqrt(3),0<= x<2pi is x=(2pi)/3