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Popular Trigonometry >

sin^3(a)=3sin(a)-4sin^3(a)

  • Pre Algebra
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Solution

sin3(a)=3sin(a)−4sin3(a)

Solution

a=2πn,a=π+2πn,a=−0.88607…+2πn,a=π+0.88607…+2πn,a=0.88607…+2πn,a=π−0.88607…+2πn
+1
Degrees
a=0∘+360∘n,a=180∘+360∘n,a=−50.76847…∘+360∘n,a=230.76847…∘+360∘n,a=50.76847…∘+360∘n,a=129.23152…∘+360∘n
Solution steps
sin3(a)=3sin(a)−4sin3(a)
Solve by substitution
sin3(a)=3sin(a)−4sin3(a)
Let: sin(a)=uu3=3u−4u3
u3=3u−4u3:u=0,u=−53​​,u=53​​
u3=3u−4u3
Switch sides3u−4u3=u3
Move u3to the left side
3u−4u3=u3
Subtract u3 from both sides3u−4u3−u3=u3−u3
Simplify3u−5u3=0
3u−5u3=0
Factor 3u−5u3:−u(5​u+3​)(5​u−3​)
3u−5u3
Factor out common term −u:−u(5u2−3)
−5u3+3u
Apply exponent rule: ab+c=abacu3=u2u=−5u2u+3u
Factor out common term −u=−u(5u2−3)
=−u(5u2−3)
Factor 5u2−3:(5​u+3​)(5​u−3​)
5u2−3
Rewrite 5u2−3 as (5​u)2−(3​)2
5u2−3
Apply radical rule: a=(a​)25=(5​)2=(5​)2u2−3
Apply radical rule: a=(a​)23=(3​)2=(5​)2u2−(3​)2
Apply exponent rule: ambm=(ab)m(5​)2u2=(5​u)2=(5​u)2−(3​)2
=(5​u)2−(3​)2
Apply Difference of Two Squares Formula: x2−y2=(x+y)(x−y)(5​u)2−(3​)2=(5​u+3​)(5​u−3​)=(5​u+3​)(5​u−3​)
=−u(5​u+3​)(5​u−3​)
−u(5​u+3​)(5​u−3​)=0
Using the Zero Factor Principle: If ab=0then a=0or b=0u=0or5​u+3​=0or5​u−3​=0
Solve 5​u+3​=0:u=−53​​
5​u+3​=0
Move 3​to the right side
5​u+3​=0
Subtract 3​ from both sides5​u+3​−3​=0−3​
Simplify5​u=−3​
5​u=−3​
Divide both sides by 5​
5​u=−3​
Divide both sides by 5​5​5​u​=5​−3​​
Simplify
5​5​u​=5​−3​​
Simplify 5​5​u​:u
5​5​u​
Cancel the common factor: 5​=u
Simplify 5​−3​​:−53​​
5​−3​​
Apply the fraction rule: b−a​=−ba​=−5​3​​
Combine same powers : y​x​​=yx​​=−53​​
u=−53​​
u=−53​​
u=−53​​
Solve 5​u−3​=0:u=53​​
5​u−3​=0
Move 3​to the right side
5​u−3​=0
Add 3​ to both sides5​u−3​+3​=0+3​
Simplify5​u=3​
5​u=3​
Divide both sides by 5​
5​u=3​
Divide both sides by 5​5​5​u​=5​3​​
Simplify
5​5​u​=5​3​​
Simplify 5​5​u​:u
5​5​u​
Cancel the common factor: 5​=u
Simplify 5​3​​:53​​
5​3​​
Combine same powers : y​x​​=yx​​=53​​
u=53​​
u=53​​
u=53​​
The solutions areu=0,u=−53​​,u=53​​
Substitute back u=sin(a)sin(a)=0,sin(a)=−53​​,sin(a)=53​​
sin(a)=0,sin(a)=−53​​,sin(a)=53​​
sin(a)=0:a=2πn,a=π+2πn
sin(a)=0
General solutions for sin(a)=0
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
a=0+2πn,a=π+2πn
a=0+2πn,a=π+2πn
Solve a=0+2πn:a=2πn
a=0+2πn
0+2πn=2πna=2πn
a=2πn,a=π+2πn
sin(a)=−53​​:a=arcsin(−53​​)+2πn,a=π+arcsin(53​​)+2πn
sin(a)=−53​​
Apply trig inverse properties
sin(a)=−53​​
General solutions for sin(a)=−53​​sin(x)=−a⇒x=arcsin(−a)+2πn,x=π+arcsin(a)+2πna=arcsin(−53​​)+2πn,a=π+arcsin(53​​)+2πn
a=arcsin(−53​​)+2πn,a=π+arcsin(53​​)+2πn
sin(a)=53​​:a=arcsin(53​​)+2πn,a=π−arcsin(53​​)+2πn
sin(a)=53​​
Apply trig inverse properties
sin(a)=53​​
General solutions for sin(a)=53​​sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πna=arcsin(53​​)+2πn,a=π−arcsin(53​​)+2πn
a=arcsin(53​​)+2πn,a=π−arcsin(53​​)+2πn
Combine all the solutionsa=2πn,a=π+2πn,a=arcsin(−53​​)+2πn,a=π+arcsin(53​​)+2πn,a=arcsin(53​​)+2πn,a=π−arcsin(53​​)+2πn
Show solutions in decimal forma=2πn,a=π+2πn,a=−0.88607…+2πn,a=π+0.88607…+2πn,a=0.88607…+2πn,a=π−0.88607…+2πn

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