What is the general solution for sin(2x)=cos(2x) ?

The general solution for sin(2x)=cos(2x) is x= pi/8+(pin)/2

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sin(2x)=cos(2x)

sin (2 x) = cos (2 x)

x = \frac{π}{8} + \frac{πn}{2}

Solution steps

sin (2 x) = cos (2 x)

Rewrite using trig identities

tan (2 x) = 1

General solutions for

tan (2 x) = 1

2 x = \frac{π}{4} + πn

Solve

2 x = \frac{π}{4} + πn : x = \frac{π}{8} + \frac{πn}{2}

x = \frac{π}{8} + \frac{πn}{2}

cos (\frac{7 π}{6})

2 cos^{2} (x) + sin (x) - 2 = 0

cos (3 π)

8 sin^{2} (x) + 2 cos (x) = 7

tan (\frac{19 π}{12})

What is the general solution for sin(2x)=cos(2x) ?
The general solution for sin(2x)=cos(2x) is x= pi/8+(pin)/2