What is the general solution for 6cos(θ)=0 ?

The general solution for 6cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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6cos(θ)=0

6 cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Degrees

θ = 9 0^{\circ} + 36 0^{\circ} n, θ = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

6 cos (θ) = 0

Divide both sides by

6

6 cos (θ) = 0

Divide both sides by

6

\frac{6 cos ( θ )}{6} = \frac{0}{6}

Simplify

cos (θ) = 0

cos (θ) = 0

General solutions for

cos (θ) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

0.175 = 0.34 sin (93.4 t)

x, cos (x y) - sin (x y) = 2

2 sin^{2} (x) - sin (x) - 2 = 0

4 cos^{2} (x) - 6 = 5 cos (x)

tan (θ) = \frac{- 3}{2}

What is the general solution for 6cos(θ)=0 ?
The general solution for 6cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin