What is the general solution for 1/(sqrt(15))=cos(x) ?

The general solution for 1/(sqrt(15))=cos(x) is x=1.30963…+2pin,x=2pi-1.30963…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(sqrt(15))=cos(x)

\frac{1}{15} = cos (x)

x = 1.30963 \dots + 2 πn, x = 2 π - 1.30963 \dots + 2 πn

Degrees

x = 75.03678 \dots^{\circ} + 36 0^{\circ} n, x = 284.96321 \dots^{\circ} + 36 0^{\circ} n

Solution steps

\frac{1}{15} = cos (x)

Switch sides

cos (x) = \frac{1}{15}

Simplify

\frac{1}{15} : \frac{15}{15}

\frac{1}{15}

Multiply by the conjugate

\frac{15}{15}

= \frac{1 \cdot 15}{15 15}

1 \cdot 15 = 15

1515 = 15

1515

Apply radical rule:

a a = a

1515 = 15

= 15

= \frac{15}{15}

cos (x) = \frac{15}{15}

Apply trig inverse properties

cos (x) = \frac{15}{15}

General solutions for

cos (x) = \frac{15}{15}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{15}{15}) + 2 πn, x = 2 π - arccos (\frac{15}{15}) + 2 πn

x = arccos (\frac{15}{15}) + 2 πn, x = 2 π - arccos (\frac{15}{15}) + 2 πn

Show solutions in decimal form

x = 1.30963 \dots + 2 πn, x = 2 π - 1.30963 \dots + 2 πn

cos^{2} (θ) = 3 sin^{2} (θ)

sinh (x) = \frac{5}{4}

3 - 4 cos (A) = 1

3 tan (x) - 2 cos (x) = 0

sin (a) = - \frac{3}{5}

What is the general solution for 1/(sqrt(15))=cos(x) ?
The general solution for 1/(sqrt(15))=cos(x) is x=1.30963…+2pin,x=2pi-1.30963…+2pin