What is the value of sin(60)-tan(45) ?

The value of sin(60)-tan(45) is (sqrt(3))/2-1

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sin(60)-tan(45)

sin (6 0^{\circ}) - tan (4 5^{\circ})

\frac{3}{2} - 1

Decimal Notation

- 0.13397 \dots

Solution steps

sin (6 0^{\circ}) - tan (4 5^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

Use the following trivial identity:

tan (4 5^{\circ}) = 1

tan (4 5^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

= \frac{3}{2} - 1

(4 cos (3 0^{\circ}))^{2}

\frac{tan ( 0 )}{sec ( 0 )}

tan (37. 5^{\circ})

\frac{2}{cos ( 2 0 ^{\circ} )}

44 sin (4 5^{\circ})

What is the value of sin(60)-tan(45) ?
The value of sin(60)-tan(45) is (sqrt(3))/2-1