What is the value of 35sin(45) ?

The value of 35sin(45) is (35sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

35sin(45)

35 sin (4 5^{\circ})

\frac{35 2}{2}

Decimal Notation

24.74873 \dots

Solution steps

35 sin (4 5^{\circ})

Use the following trivial identity:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= 35 \cdot \frac{2}{2}

Simplify

35 \cdot \frac{2}{2} : \frac{35 2}{2}

35 \cdot \frac{2}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 35}{2}

Apply radical rule:

2 = 2^{\frac{1}{2}}

= \frac{35 \cdot 2 ^{\frac{1}{2}}}{2}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{35}{2 ^{1 - \frac{1}{2}}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{35}{2 ^{\frac{1}{2}}}

Apply radical rule:

2^{\frac{1}{2}} = 2

= \frac{35}{2}

Rationalize

\frac{35}{2} : \frac{35 2}{2}

\frac{35}{2}

Multiply by the conjugate

\frac{2}{2}

= \frac{35 2}{2 2}

22 = 2

22

Apply radical rule:

a a = a

22 = 2

= 2

= \frac{35 2}{2}

= \frac{35 2}{2}

= \frac{35 2}{2}

arcsin (0.1915)

(5 sin (3^{\circ}) + 7 cos (8 7^{\circ})) csc (3^{\circ})

cos (4 0^{\circ}) + sin (4 0^{\circ})

\frac{4}{3} 3 cos (- \frac{4 π}{3})

\frac{6 ( 9.81 ) - 6 ( 9.81 ) sin ( 3 0 ^{\circ} )}{6 + 6}