What is the value of arccos^2((sqrt(2))/2) ?

The value of arccos^2((sqrt(2))/2) is (pi^2)/(16)

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arccos^2((sqrt(2))/2)

arccos^{2} (\frac{2}{2})

\frac{π ^{2}}{16}

Decimal Notation

35.34

Solution steps

arccos^{2} (\frac{2}{2})

Use the following trivial identity:

arccos (\frac{2}{2}) = \frac{π}{4}

arccos (\frac{2}{2})

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{4}

= (\frac{π}{4})^{2}

Simplify

(\frac{π}{4})^{2} : \frac{π ^{2}}{16}

(\frac{π}{4})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{π ^{2}}{4 ^{2}}

4^{2} = 16

= \frac{π ^{2}}{16}

= \frac{π ^{2}}{16}

π + cos (π)

- 2 tanh (0)

arccos (0.116)

10 (cos (\frac{π}{3}) + i sin (\frac{π}{3}))

ln (sin (\frac{3 π}{4}))

What is the value of arccos^2((sqrt(2))/2) ?
The value of arccos^2((sqrt(2))/2) is (pi^2)/(16)