What is the value of sin(40)cos(20)+cos(40)sin(20) ?

The value of sin(40)cos(20)+cos(40)sin(20) is (sqrt(3))/2

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sin(40)cos(20)+cos(40)sin(20)

sin (4 0^{\circ}) cos (2 0^{\circ}) + cos (4 0^{\circ}) sin (2 0^{\circ})

\frac{3}{2}

Solution steps

sin (4 0^{\circ}) cos (2 0^{\circ}) + cos (4 0^{\circ}) sin (2 0^{\circ})

Rewrite using trig identities:

sin (6 0^{\circ})

= sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

= \frac{3}{2}

e^{s i n (\frac{π}{2})}

2 sin (157. 5^{\circ}) cos (157. 5^{\circ})

sec (3 5^{\circ})

2 \cdot sin (\frac{π}{4})

tan (arcsec (4))

What is the value of sin(40)cos(20)+cos(40)sin(20) ?
The value of sin(40)cos(20)+cos(40)sin(20) is (sqrt(3))/2