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Popular Trigonometry >

(cos(pi/2)-cos((4pi)/3))/(2sin((5pi)/6))

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Solution

2sin(65π​)cos(2π​)−cos(34π​)​

Solution

21​
+1
Decimal
0.5
Solution steps
2sin(65π​)cos(2π​)−cos(34π​)​
Rewrite using trig identities:cos(34π​)=1−2sin2(32π​)
cos(34π​)
Write cos(34π​)as cos(2⋅32π​)=cos(2⋅32π​)
Use the Double Angle identity: cos(2x)=1−2sin2(x)=1−2sin2(32π​)
=2sin(65π​)cos(2π​)−(1−2sin2(32π​))​
Simplify=2sin(65π​)cos(2π​)−1+2sin2(32π​)​
Use the following trivial identity:cos(2π​)=0
cos(2π​)
cos(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
=0
Use the following trivial identity:sin(32π​)=23​​
sin(32π​)
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=23​​
Use the following trivial identity:sin(65π​)=21​
sin(65π​)
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=21​
=2⋅21​0−1+2(23​​)2​
Simplify 2⋅21​0−1+2(23​​)2​:21​
2⋅21​0−1+2(23​​)2​
Subtract the numbers: 0−1=−1=2⋅21​2(23​​)2−1​
Multiply 2⋅21​:1
2⋅21​
Multiply fractions: a⋅cb​=ca⋅b​=21⋅2​
Cancel the common factor: 2=1
=12(23​​)2−1​
2(23​​)2=23​
2(23​​)2
(23​​)2=223​
(23​​)2
Apply exponent rule: (ba​)c=bcac​=22(3​)2​
(3​)2:3
Apply radical rule: a​=a21​=(321​)2
Apply exponent rule: (ab)c=abc=321​⋅2
21​⋅2=1
21​⋅2
Multiply fractions: a⋅cb​=ca⋅b​=21⋅2​
Cancel the common factor: 2=1
=3
=223​
=2⋅223​
Multiply fractions: a⋅cb​=ca⋅b​=223⋅2​
Multiply the numbers: 3⋅2=6=226​
Factor 6:2⋅3
Factor 6=2⋅3
=222⋅3​
Cancel the common factor: 2=23​
=123​−1​
Join 23​−1:21​
23​−1
Convert element to fraction: 1=21⋅2​=23​−21⋅2​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=23−1⋅2​
3−1⋅2=1
3−1⋅2
Multiply the numbers: 1⋅2=2=3−2
Subtract the numbers: 3−2=1=1
=21​
=121​​
Apply the fraction rule: 1a​=a=21​
=21​

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Frequently Asked Questions (FAQ)

  • What is the value of (cos(pi/2)-cos((4pi)/3))/(2sin((5pi)/6)) ?

    The value of (cos(pi/2)-cos((4pi)/3))/(2sin((5pi)/6)) is 1/2
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