What is the value of cos^2(150)-sin^2(150) ?

The value of cos^2(150)-sin^2(150) is 1/2

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cos^2(150)-sin^2(150)

cos^{2} (15 0^{\circ}) - sin^{2} (15 0^{\circ})

\frac{1}{2}

Solution steps

cos^{2} (15 0^{\circ}) - sin^{2} (15 0^{\circ})

Use the following trivial identity:

cos (15 0^{\circ}) = - \frac{3}{2}

Use the following trivial identity:

sin (15 0^{\circ}) = \frac{1}{2}

= (- \frac{3}{2})^{2} - (\frac{1}{2})^{2}

Simplify

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2} : \frac{1}{2}

= \frac{1}{2}

tan (- 3)

1 cos (0)

2 cos (- \frac{π}{2})

cos (0.4)

cos (0.7)

What is the value of cos^2(150)-sin^2(150) ?
The value of cos^2(150)-sin^2(150) is 1/2