What is the value of (tan^2(-(5pi)/6))/(sec(-(5pi)/6)+1) ?

The value of (tan^2(-(5pi)/6))/(sec(-(5pi)/6)+1) is -(2sqrt(3)+3)/3

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Popular Trigonometry >

(tan^2(-(5pi)/6))/(sec(-(5pi)/6)+1)

Solution

\frac{tan ^{2} ( - \frac{5 π}{6} )}{sec ( - \frac{5 π}{6} ) + 1}

Solution

- \frac{2 3 + 3}{3}

Decimal

- 2.15470 \dots

Solution steps

\frac{tan ^{2} ( - \frac{5 π}{6} )}{sec ( - \frac{5 π}{6} ) + 1}

Use the following property:

sec (- x) = sec (x)

sec (- \frac{5 π}{6}) = sec (\frac{5 π}{6})

= \frac{tan ^{2} ( - \frac{5 π}{6} )}{sec ( \frac{5 π}{6} ) + 1}

Use the following property:

tan (- x) = - tan (x)

tan (- \frac{5 π}{6}) = - tan (\frac{5 π}{6})

= \frac{( - tan ( \frac{5 π}{6} ) ) ^{2}}{sec ( \frac{5 π}{6} ) + 1}

Simplify

= \frac{tan ^{2} ( \frac{5 π}{6} )}{sec ( \frac{5 π}{6} ) + 1}

Rewrite using trig identities:

tan^{2} (\frac{5 π}{6}) = sec^{2} (\frac{5 π}{6}) - 1

tan^{2} (\frac{5 π}{6})

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

tan^{2} (x) = sec^{2} (x) - 1

= sec^{2} (\frac{5 π}{6}) - 1

= \frac{sec ^{2} ( \frac{5 π}{6} ) - 1}{sec ( \frac{5 π}{6} ) + 1}

Use the following trivial identity:

sec (\frac{5 π}{6}) = - \frac{2 3}{3}

sec (\frac{5 π}{6})

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= - \frac{2 3}{3}

= \frac{( - \frac{2 3}{3} ) ^{2} - 1}{- \frac{2 3}{3} + 1}

Simplify

\frac{( - \frac{2 3}{3} ) ^{2} - 1}{- \frac{2 3}{3} + 1} : - \frac{2 3 + 3}{3}

\frac{( - \frac{2 3}{3} ) ^{2} - 1}{- \frac{2 3}{3} + 1}

(- \frac{2 3}{3})^{2} - 1 = (\frac{2 3}{3})^{2} - 1

(- \frac{2 3}{3})^{2} - 1

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{2 3}{3})^{2} = (\frac{2 3}{3})^{2}

= (\frac{2 3}{3})^{2} - 1

= \frac{( \frac{2 3}{3} ) ^{2} - 1}{- \frac{2 3}{3} + 1}

Join

- \frac{2 3}{3} + 1 : \frac{- 2 + 3}{3}

- \frac{2 3}{3} + 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= - \frac{2 3}{3} + \frac{1 \cdot 3}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 3 + 1 \cdot 3}{3}

Multiply the numbers:

1 \cdot 3 = 3

= \frac{- 2 3 + 3}{3}

Factor

- 23 + 3 : 3 (- 2 + 3)

- 23 + 3

3 = 33

= - 23 + 33

Factor out common term

3

= 3 (- 2 + 3)

= \frac{3 ( - 2 + 3 )}{3}

Cancel

\frac{3 ( - 2 + 3 )}{3} : \frac{- 2 + 3}{3}

\frac{3 ( - 2 + 3 )}{3}

Apply radical rule:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}} ( 3 - 2 )}{3}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{- 2 + 3}{3 ^{1 - \frac{1}{2}}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{- 2 + 3}{3 ^{\frac{1}{2}}}

Apply radical rule:

3^{\frac{1}{2}} = 3

= \frac{- 2 + 3}{3}

= \frac{- 2 + 3}{3}

= \frac{( \frac{2 3}{3} ) ^{2} - 1}{\frac{- 2 + 3}{3}}

(\frac{2 3}{3})^{2} = \frac{2 ^{2}}{3}

(\frac{2 3}{3})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 3 ) ^{2}}{3 ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(23)^{2} = 2^{2} (3)^{2}

= \frac{2 ^{2} ( 3 ) ^{2}}{3 ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{2 ^{2} \cdot 3}{3 ^{2}}

Cancel the common factor:

3

= \frac{2 ^{2}}{3}

= \frac{\frac{2 ^{2}}{3} - 1}{\frac{- 2 + 3}{3}}

2^{2} = 4

= \frac{\frac{4}{3} - 1}{\frac{- 2 + 3}{3}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( \frac{4}{3} - 1 ) 3}{- 2 + 3}

Join

\frac{4}{3} - 1 : \frac{1}{3}

\frac{4}{3} - 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= \frac{4}{3} - \frac{1 \cdot 3}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 - 1 \cdot 3}{3}

4 - 1 \cdot 3 = 1

4 - 1 \cdot 3

Multiply the numbers:

1 \cdot 3 = 3

= 4 - 3

Subtract the numbers:

4 - 3 = 1

= 1

= \frac{1}{3}

= \frac{3 \frac{1}{3}}{- 2 + 3}

Multiply

\frac{1}{3} 3 : \frac{1}{3}

\frac{1}{3} 3

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 3}{3}

Multiply:

1 \cdot 3 = 3

= \frac{3}{3}

Apply radical rule:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Apply radical rule:

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= \frac{\frac{1}{3}}{- 2 + 3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{1}{3 ( - 2 + 3 )}

Expand

3 (- 2 + 3) : - 23 + 3

3 (- 2 + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = - 2, c = 3

= 3 (- 2) + 33

Apply minus-plus rules

+ (- a) = - a

= - 23 + 33

Apply radical rule:

a a = a

33 = 3

= - 23 + 3

= \frac{1}{- 2 3 + 3}

Rationalize

\frac{1}{- 2 3 + 3} : - \frac{2 3 + 3}{3}

\frac{1}{- 2 3 + 3}

Multiply by the conjugate

\frac{2 3 + 3}{2 3 + 3}

= \frac{1 \cdot ( 2 3 + 3 )}{( - 2 3 + 3 ) ( 2 3 + 3 )}

1 \cdot (23 + 3) = 23 + 3

(- 23 + 3) (23 + 3) = - 3

(- 23 + 3) (23 + 3)

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = 3, b = 23

= 3^{2} - (23)^{2}

Simplify

3^{2} - (23)^{2} : - 3

3^{2} - (23)^{2}

3^{2} = 9

3^{2}

3^{2} = 9

= 9

(23)^{2} = 12

(23)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 2^{2} (3)^{2}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= 2^{2} \cdot 3

2^{2} = 4

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 9 - 12

Subtract the numbers:

9 - 12 = - 3

= - 3

= - 3

= \frac{2 3 + 3}{- 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 3 + 3}{3}

= - \frac{2 3 + 3}{3}

= - \frac{2 3 + 3}{3}

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Frequently Asked Questions (FAQ)

What is the value of (tan^2(-(5pi)/6))/(sec(-(5pi)/6)+1) ?
The value of (tan^2(-(5pi)/6))/(sec(-(5pi)/6)+1) is -(2sqrt(3)+3)/3