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Popular Trigonometry >

(pi/3 cos(pi/3)-sin(pi/3))/((pi/3)^2)

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Solution

(3π​)23π​cos(3π​)−sin(3π​)​

Solution

2π23(π−33​)​
+1
Decimal
−0.31225…
Solution steps
(3π​)23π​cos(3π​)−sin(3π​)​
Use the following trivial identity:cos(3π​)=21​
cos(3π​)
cos(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
=21​
Use the following trivial identity:sin(3π​)=23​​
sin(3π​)
sin(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sin(x)021​22​​23​​123​​22​​21​​xπ67π​45π​34π​23π​35π​47π​611π​​sin(x)0−21​−22​​−23​​−1−23​​−22​​−21​​​
=23​​
=(3π​)23π​⋅21​−23​​​
Simplify (3π​)23π​⋅21​−23​​​:2π23(π−33​)​
(3π​)23π​⋅21​−23​​​
(3π​)2=32π2​
(3π​)2
Apply exponent rule: (ba​)c=bcac​=32π2​
=32π2​3π​⋅21​−23​​​
3π​⋅21​=6π​
3π​⋅21​
Multiply fractions: ba​⋅dc​=b⋅da⋅c​=3⋅2π1​
Multiply: π1=π=3⋅2π​
Multiply the numbers: 3⋅2=6=6π​
=32π2​6π​−23​​​
Apply the fraction rule: cb​a​=ba⋅c​=π2(6π​−23​​)⋅32​
Join 6π​−23​​:6π−33​​
6π​−23​​
Least Common Multiplier of 6,2:6
6,2
Least Common Multiplier (LCM)
Prime factorization of 6:2⋅3
6
6divides by 26=3⋅2=2⋅3
2,3 are all prime numbers, therefore no further factorization is possible=2⋅3
Prime factorization of 2:2
2
2 is a prime number, therefore no factorization is possible=2
Multiply each factor the greatest number of times it occurs in either 6 or 2=2⋅3
Multiply the numbers: 2⋅3=6=6
Adjust Fractions based on the LCM
Multiply each numerator by the same amount needed to multiply its
corresponding denominator to turn it into the LCM 6
For 23​​:multiply the denominator and numerator by 323​​=2⋅33​⋅3​=63​⋅3​
=6π​−63​⋅3​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=6π−3​⋅3​
=π232⋅6π−33​​​
32=9=π29⋅6π−33​​​
Multiply 6π−3​⋅3​⋅9:23(π−33​)​
6π−3​⋅3​⋅9
Multiply fractions: a⋅cb​=ca⋅b​=6(π−3​⋅3)⋅9​
Cancel the common factor: 3=23(π−33​)​
=π223(π−33​)​​
Apply the fraction rule: acb​​=c⋅ab​=2π23(π−33​)​
=2π23(π−33​)​

Popular Examples

arccos((sqrt(5))/2)arctan(1.27)sin(-200)5sin^2(pi)cos((12pi)/7)

Frequently Asked Questions (FAQ)

  • What is the value of (pi/3 cos(pi/3)-sin(pi/3))/((pi/3)^2) ?

    The value of (pi/3 cos(pi/3)-sin(pi/3))/((pi/3)^2) is (3(pi-3sqrt(3)))/(2pi^2)
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