What is the value of cos(40)cos(10)+sin(40)sin(10) ?

The value of cos(40)cos(10)+sin(40)sin(10) is (sqrt(3))/2

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cos(40)cos(10)+sin(40)sin(10)

cos (4 0^{\circ}) cos (1 0^{\circ}) + sin (4 0^{\circ}) sin (1 0^{\circ})

\frac{3}{2}

Solution steps

cos (4 0^{\circ}) cos (1 0^{\circ}) + sin (4 0^{\circ}) sin (1 0^{\circ})

Rewrite using trig identities:

cos (3 0^{\circ})

= cos (3 0^{\circ})

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

= \frac{3}{2}

tan (- \frac{19 π}{6})

1 - 2 arctan (1)

tan (66 0^{\circ})

arcsin (0.23)

600 cos (3 0^{\circ})

What is the value of cos(40)cos(10)+sin(40)sin(10) ?
The value of cos(40)cos(10)+sin(40)sin(10) is (sqrt(3))/2