Is (sin(x)sin(x))/(cos(x))=cos(x) ?

The answer to whether (sin(x)sin(x))/(cos(x))=cos(x) is False

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prove (sin(x)sin(x))/(cos(x))=cos(x)

prove

\frac{sin ( x ) sin ( x )}{cos ( x )} = cos (x)

False

Solution steps

\frac{sin ( x ) sin ( x )}{cos ( x )} = cos (x)

Show that the two sides are not equal

For

\frac{sin ( x ) sin ( x )}{cos ( x )} = cos (x)

plug in

x = 0

\frac{sin ( 0 ) sin ( 0 )}{cos ( 0 )} = 0

\frac{sin ( 0 ) sin ( 0 )}{cos ( 0 )}

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= \frac{0 \cdot 0}{1}

Simplify

= 0

cos (0) = 1

cos (0)

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= 1

The two sides are not equal

\Rightarrow False

p ro v e \frac{cos ( x )}{5} = \frac{1}{5} \cdot cos (x)

p ro v e \frac{1 + tan ( x )}{sec ( x )} = cos (x) + sin (x)

p ro v e \frac{sin ( 4 x )}{4} = \frac{sin ( x ) cos ( x )}{2}

p ro v e \frac{sin ( x ) tan ( x )}{cos ( x ) + 1} = sec (x) - 1

p ro v e sin (a + b) - sin (a - b) = 2 sin (a) sin (b)

Is (sin(x)sin(x))/(cos(x))=cos(x) ?
The answer to whether (sin(x)sin(x))/(cos(x))=cos(x) is False