Is (cos(2θ))/(-sin^2(θ))=cos^2(θ) ?

The answer to whether (cos(2θ))/(-sin^2(θ))=cos^2(θ) is False

prove (cos(2θ))/(-sin^2(θ))=cos^2(θ)

prove

\frac{cos ( 2 θ )}{- sin ^{2} ( θ )} = cos^{2} (θ)

False

Solution steps

\frac{cos ( 2 θ )}{- sin ^{2} ( θ )} = cos^{2} (θ)

Show that the two sides are not equal

For

\frac{cos ( 2 θ )}{- sin ^{2} ( θ )} = cos^{2} (θ)

plug in

θ = 1

\frac{cos ( 2 \cdot 1 )}{- sin ^{2} ( 1 )} = 0.58771 \dots

\frac{cos ( 2 \cdot 1 )}{- sin ^{2} ( 1 )}

Refine to a decimal form

= 0.58771 \dots

cos^{2} (1) = 0.29192 \dots

cos^{2} (1)

Refine to a decimal form

= 0.29192 \dots

The two sides are not equal

\Rightarrow False

p ro v e sin (x) + cot (x) (cos (x)) = csc (x)

p ro v e \frac{1}{csc ( x ) - 1} = \frac{sin ( x )}{1}

p ro v e sec (θ) cos (θ) csc (θ) = cot (θ)

p ro v e csc^{2} (x) (1 - cos^{2} (x)) = tan (42 0^{\circ})

p ro v e cos (θ + 3 0^{\circ}) - sin (θ + 6 0^{\circ}) = - sin (θ)

Is (cos(2θ))/(-sin^2(θ))=cos^2(θ) ?
The answer to whether (cos(2θ))/(-sin^2(θ))=cos^2(θ) is False