Is (tan^2(X))/(1+cot^2(X))=sin^4(X) ?

The answer to whether (tan^2(X))/(1+cot^2(X))=sin^4(X) is False

prove (tan^2(X))/(1+cot^2(X))=sin^4(X)

prove

\frac{tan ^{2} ( X )}{1 + cot ^{2} ( X )} = sin^{4} (X)

False

Solution steps

\frac{tan ^{2} ( X )}{1 + cot ^{2} ( X )} = sin^{4} (X)

Show that the two sides are not equal

For

\frac{tan ^{2} ( X )}{1 + cot ^{2} ( X )} = sin^{4} (X)

plug in

X = 1

\frac{tan ^{2} ( 1 )}{1 + cot ^{2} ( 1 )} = 1.71744 \dots

\frac{tan ^{2} ( 1 )}{1 + cot ^{2} ( 1 )}

Refine to a decimal form

= 1.71744 \dots

sin^{4} (1) = 0.50136 \dots

sin^{4} (1)

Refine to a decimal form

= 0.50136 \dots

The two sides are not equal

\Rightarrow False

p ro v e sin (x) + cot (x) cos (x) = \frac{1}{sin ( x )}

p ro v e 1 + cos (6 x) = 2 cos^{2} (3 x)

p ro v e \frac{sec ( a )}{cot ( a ) + tan ( a )} = sin (a)

p ro v e \frac{4 + 2 sin ( θ )}{1 - sin ( θ )} = 3

p ro v e \frac{sin ( 4 x )}{4} = 4 \frac{sin ( x ) cos ( x )}{4}

Is (tan^2(X))/(1+cot^2(X))=sin^4(X) ?
The answer to whether (tan^2(X))/(1+cot^2(X))=sin^4(X) is False