Is 1/(-sin(x))=sec(x)tan(x) ?

The answer to whether 1/(-sin(x))=sec(x)tan(x) is False

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prove 1/(-sin(x))=sec(x)tan(x)

prove

\frac{1}{- sin ( x )} = sec (x) tan (x)

False

Solution steps

\frac{1}{- sin ( x )} = sec (x) tan (x)

Show that the two sides are not equal

For

\frac{1}{- sin ( x )} = sec (x) tan (x)

plug in

x = 1

\frac{1}{- sin ( 1 )} = - 1.18839 \dots

\frac{1}{- sin ( 1 )}

Refine to a decimal form

= - 1.18839 \dots

sec (1) tan (1) = 2.88247 \dots

sec (1) tan (1)

Refine to a decimal form

= 2.88247 \dots

The two sides are not equal

\Rightarrow False

p ro v e 6 cos (θ) = 6 cos (- θ)

p ro v e \frac{( tan ( 2 x ) + cot ( 2 x ) )}{csc ( 2 x )} = sec (2 x)

p ro v e (cos (θ) - sin (θ))^{2} = 1

p ro v e cos (x) = 1 = cos (0) = 1

p ro v e (tan (x) + 1) (tan (x) - 1) = sec^{2} (x) - 2

Is 1/(-sin(x))=sec(x)tan(x) ?
The answer to whether 1/(-sin(x))=sec(x)tan(x) is False