Is csc(x)-cos^2(x)-csc(x)=sin(x) ?

The answer to whether csc(x)-cos^2(x)-csc(x)=sin(x) is False

prove csc(x)-cos^2(x)-csc(x)=sin(x)

prove

csc (x) - cos^{2} (x) - csc (x) = sin (x)

False

Solution steps

csc (x) - cos^{2} (x) - csc (x) = sin (x)

Show that the two sides are not equal

For

csc (x) - cos^{2} (x) - csc (x) = sin (x)

plug in

x = 1

csc (1) - cos^{2} (1) - csc (1) = - 0.29192 \dots

csc (1) - cos^{2} (1) - csc (1)

Refine to a decimal form

= - 0.29192 \dots

sin (1) = 0.84147 \dots

sin (1)

Refine to a decimal form

= 0.84147 \dots

The two sides are not equal

\Rightarrow False

p ro v e 1 - \frac{cos ^{2} ( x )}{1 + sin ^{2} ( x )} = sin (s)

p ro v e csc (x) = \frac{1}{sin ( x )} = 2

p ro v e 5 - 5 + 5 - 5 - 5 - 5 + 5 - 5 + 5 + 5 - 5 = - 5

p ro v e 1 + cos^{4} (x) - sin^{4} (x) = 2 cos^{2} (x)

p ro v e cot (x) - sec (x) csc (x) cos (2 x) = tan (x)

Is csc(x)-cos^2(x)-csc(x)=sin(x) ?
The answer to whether csc(x)-cos^2(x)-csc(x)=sin(x) is False