Is cos(x)+cot(x)+sin(x)=csc(x) ?

The answer to whether cos(x)+cot(x)+sin(x)=csc(x) is False

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prove cos(x)+cot(x)+sin(x)=csc(x)

prove

cos (x) + cot (x) + sin (x) = csc (x)

False

Solution steps

cos (x) + cot (x) + sin (x) = csc (x)

Show that the two sides are not equal

For

cos (x) + cot (x) + sin (x) = csc (x)

plug in

x = 1

cos (1) + cot (1) + sin (1) = 2.02386 \dots

cos (1) + cot (1) + sin (1)

Refine to a decimal form

= 2.02386 \dots

csc (1) = 1.18839 \dots

csc (1)

Refine to a decimal form

= 1.18839 \dots

The two sides are not equal

\Rightarrow False

p ro v e cos (- θ) csc (- θ) tan (- θ) = 1

p ro v e sec (x) - 2 tan (x) = 0

p ro v e cos (3 θ) = cos (θ) (cos^{2} (θ) - 3 sin^{2} (θ))

p ro v e cos (θ) = sec (θ) - (sin (θ)) (tan (θ))

p ro v e cos (2 x - 90) = 2 sin (x) cos (x)

Is cos(x)+cot(x)+sin(x)=csc(x) ?
The answer to whether cos(x)+cot(x)+sin(x)=csc(x) is False