Is (sin(y^2))/(cos(y))=sec(y)-cos(y) ?

The answer to whether (sin(y^2))/(cos(y))=sec(y)-cos(y) is False

prove (sin(y^2))/(cos(y))=sec(y)-cos(y)

prove

\frac{sin ( y ^{2} )}{cos ( y )} = sec (y) - cos (y)

False

Solution steps

\frac{sin ( y ^{2} )}{cos ( y )} = sec (y) - cos (y)

Show that the two sides are not equal

For

\frac{sin ( y ^{2} )}{cos ( y )} = sec (y) - cos (y)

plug in

y = 1

\frac{sin ( 1 ^{2} )}{cos ( 1 )} = 1.55740 \dots

\frac{sin ( 1 ^{2} )}{cos ( 1 )}

Refine to a decimal form

= 1.55740 \dots

sec (1) - cos (1) = 1.31051 \dots

sec (1) - cos (1)

Refine to a decimal form

= 1.31051 \dots

The two sides are not equal

\Rightarrow False

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Is (sin(y^2))/(cos(y))=sec(y)-cos(y) ?
The answer to whether (sin(y^2))/(cos(y))=sec(y)-cos(y) is False