Is sin(cot(x)+tan(x))=sec(x) ?

The answer to whether sin(cot(x)+tan(x))=sec(x) is False

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prove sin(cot(x)+tan(x))=sec(x)

prove

sin (cot (x) + tan (x)) = sec (x)

False

Solution steps

sin (cot (x) + tan (x)) = sec (x)

Show that the two sides are not equal

For

sin (cot (x) + tan (x)) = sec (x)

plug in

x = 1

sin (cot (1) + tan (1)) = 0.80879 \dots

sin (cot (1) + tan (1))

Refine to a decimal form

= 0.80879 \dots

sec (1) = 1.85081 \dots

sec (1)

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

p ro v e sin^{2} (2 x) = 4 sin^{2} (x) \cdot cos^{2} (x)

p ro v e \frac{sec ( x ) csc ( x )}{2} = csc (2 x)

p ro v e - sec^{2} (x) = - tan^{2} (x) - 1

p ro v e tan (4 x) \cdot cos (4 x) = sin (4 x)

p ro v e tan (θ) = csc (θ) sec (θ) - cot (θ)

Is sin(cot(x)+tan(x))=sec(x) ?
The answer to whether sin(cot(x)+tan(x))=sec(x) is False