Is (cot^2(x)-1)/(csc(x)+1)=csc(x)-1 ?

The answer to whether (cot^2(x)-1)/(csc(x)+1)=csc(x)-1 is False

prove (cot^2(x)-1)/(csc(x)+1)=csc(x)-1

prove

\frac{cot ^{2} ( x ) - 1}{csc ( x ) + 1} = csc (x) - 1

False

Solution steps

\frac{cot ^{2} ( x ) - 1}{csc ( x ) + 1} = csc (x) - 1

Show that the two sides are not equal

For

\frac{cot ^{2} ( x ) - 1}{csc ( x ) + 1} = csc (x) - 1

plug in

x = 1

\frac{cot ^{2} ( 1 ) - 1}{csc ( 1 ) + 1} = - 0.26856 \dots

\frac{cot ^{2} ( 1 ) - 1}{csc ( 1 ) + 1}

Refine to a decimal form

= - 0.26856 \dots

csc (1) - 1 = 0.18839 \dots

csc (1) - 1

Refine to a decimal form

= 0.18839 \dots

The two sides are not equal

\Rightarrow False

p ro v e \frac{( cos ( π + x ) )}{cos ( \frac{3 π}{2} - x )} = cot (x)

p ro v e sin (12 0^{\circ}) = sin (18 0^{\circ} - 6 0^{\circ})

p ro v e \frac{sin ( 2 x )}{tan ( 2 x )} = 1 - 2 sin^{2} (x)

p ro v e cot (a) = tan (\frac{π}{2} - a)

p ro v e cos (- x) + \frac{sin ( - x )}{cot ( - x )} = sec (x)

Is (cot^2(x)-1)/(csc(x)+1)=csc(x)-1 ?
The answer to whether (cot^2(x)-1)/(csc(x)+1)=csc(x)-1 is False