Is (1+sin(θ))/(cos(θ))=sec(θ)+cot(θ) ?

The answer to whether (1+sin(θ))/(cos(θ))=sec(θ)+cot(θ) is False

prove (1+sin(θ))/(cos(θ))=sec(θ)+cot(θ)

prove

\frac{1 + sin ( θ )}{cos ( θ )} = sec (θ) + cot (θ)

False

Solution steps

\frac{1 + sin ( θ )}{cos ( θ )} = sec (θ) + cot (θ)

Show that the two sides are not equal

For

\frac{1 + sin ( θ )}{cos ( θ )} = sec (θ) + cot (θ)

plug in

θ = 1

\frac{1 + sin ( 1 )}{cos ( 1 )} = 3.40822 \dots

\frac{1 + sin ( 1 )}{cos ( 1 )}

Refine to a decimal form

= 3.40822 \dots

sec (1) + cot (1) = 2.49290 \dots

sec (1) + cot (1)

Refine to a decimal form

= 2.49290 \dots

The two sides are not equal

\Rightarrow False

p ro v e (1 + sin (θ)) (1 - sin (θ)) = cos^{2} (x)

p ro v e sin^{2} (θ) = csc (θ)

p ro v e \frac{1 - cot ( a )}{csc ( a )} = sin (a) - cos (a)

p ro v e sin (9 0^{\circ} - θ) = cos (θ)

p ro v e cos (a) sec (a) = 1

Is (1+sin(θ))/(cos(θ))=sec(θ)+cot(θ) ?
The answer to whether (1+sin(θ))/(cos(θ))=sec(θ)+cot(θ) is False