Is sin(3a)+sin(a)=4sin(a)-4sin(3a) ?

The answer to whether sin(3a)+sin(a)=4sin(a)-4sin(3a) is False

prove sin(3a)+sin(a)=4sin(a)-4sin(3a)

prove

sin (3 a) + sin (a) = 4 sin (a) - 4 sin (3 a)

False

Solution steps

sin (3 a) + sin (a) = 4 sin (a) - 4 sin (3 a)

Show that the two sides are not equal

For

sin (3 a) + sin (a) = 4 sin (a) - 4 sin (3 a)

plug in

a = 1

sin (3 \cdot 1) + sin (1) = 0.98259 \dots

sin (3 \cdot 1) + sin (1)

Refine to a decimal form

= 0.98259 \dots

4 sin (1) - 4 sin (3 \cdot 1) = 2.80140 \dots

4 sin (1) - 4 sin (3 \cdot 1)

Refine to a decimal form

= 2.80140 \dots

The two sides are not equal

\Rightarrow False

p ro v e tan (β) = \frac{cos ( β )}{sin ( β ) cot ^{2} ( β )}

p ro v e \frac{sin ^{2} ( x )}{cos ( x )} = sin (x) tan (x)

p ro v e csc^{2} (x) sec^{2} (x) = sec^{2} (x) + csc^{2} (x)

p ro v e \frac{sin ( x ) + cos ( x )}{cos ( x )} = 1 + tan (x)

p ro v e \frac{1 + sin ( - x )}{cos ( x ) tan ( x ) - 1} = - 1

Is sin(3a)+sin(a)=4sin(a)-4sin(3a) ?
The answer to whether sin(3a)+sin(a)=4sin(a)-4sin(3a) is False