Is sec(A)csc(A)=csc(A)tan(A) ?

The answer to whether sec(A)csc(A)=csc(A)tan(A) is False

prove sec(A)csc(A)=csc(A)tan(A)

prove

sec (A) csc (A) = csc (A) tan (A)

False

Solution steps

sec (A) csc (A) = csc (A) tan (A)

Show that the two sides are not equal

For

sec (A) csc (A) = csc (A) tan (A)

plug in

A = 1

sec (1) csc (1) = 2.19950 \dots

sec (1) csc (1)

Refine to a decimal form

= 2.19950 \dots

csc (1) tan (1) = 1.85081 \dots

csc (1) tan (1)

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

p ro v e sin (x) \cdot tan (x) + cos (- x) = sec (x)

p ro v e cos (2 α) = cos^{2} (α) - sin^{2} (α)

p ro v e \frac{tan ( x )}{1 + tan ^{2} ( x )} = cos (x) sin (x)

p ro v e 2 csc (2 x) = \frac{1}{sin ( x ) cos ( x )}

p ro v e (1 + csc (θ)) (1 - sin (θ)) = csc (θ) - sin (θ)

Is sec(A)csc(A)=csc(A)tan(A) ?
The answer to whether sec(A)csc(A)=csc(A)tan(A) is False