Is 1+tan^2(60)=sec^2(60) ?

The answer to whether 1+tan^2(60)=sec^2(60) is True

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prove 1+tan^2(60)=sec^2(60)

prove

1 + tan^{2} (6 0^{\circ}) = sec^{2} (6 0^{\circ})

True

Solution steps

1 + tan^{2} (6 0^{\circ}) = sec^{2} (6 0^{\circ})

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow True

p ro v e sin (x) = sin (x + 2 π)

p ro v e 1 + cos (t) = \frac{sin ^{2} ( t )}{1 - cos ( t )}

p ro v e cos (3 x) = cos (x) (1 - 4 sin^{2} (x))

p ro v e tan (A) + cot (A) = \frac{2}{sin ( 2 A )}

p ro v e \frac{1 - cos ^{2} ( x )}{1 + sin ( x )} = sin (x)