What is the general solution for 2sin(θ)+sqrt(2)=0 ?

The general solution for 2sin(θ)+sqrt(2)=0 is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin

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2sin(θ)+sqrt(2)=0

2 sin (θ) + 2 = 0

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

2 sin (θ) + 2 = 0

Move

2

to the right side

2 sin (θ) = - 2

Divide both sides by

2

sin (θ) = - \frac{2}{2}

General solutions for

sin (θ) = - \frac{2}{2}

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

cos (31 5^{\circ})

- cos (1)

sec (π)

sec (4 5^{\circ})

sec^{2} (x)

What is the general solution for 2sin(θ)+sqrt(2)=0 ?
The general solution for 2sin(θ)+sqrt(2)=0 is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin