Is sin(x)cos(x)+sin(3x)sec(x)=tan(x) ?

The answer to whether sin(x)cos(x)+sin(3x)sec(x)=tan(x) is False

prove sin(x)cos(x)+sin(3x)sec(x)=tan(x)

prove

sin (x) cos (x) + sin (3 x) sec (x) = tan (x)

False

Solution steps

sin (x) cos (x) + sin (3 x) sec (x) = tan (x)

Show that the two sides are not equal

For

sin (x) cos (x) + sin (3 x) sec (x) = tan (x)

plug in

x = 1

sin (1) cos (1) + sin (3 \cdot 1) sec (1) = 0.71583 \dots

sin (1) cos (1) + sin (3 \cdot 1) sec (1)

Refine to a decimal form

= 0.71583 \dots

tan (1) = 1.55740 \dots

tan (1)

Refine to a decimal form

= 1.55740 \dots

The two sides are not equal

\Rightarrow False

p ro v e (1 + sec (x)) (1 - cos (x)) = sin (x) tan (x)

p ro v e sec (x) \cdot sin (x) = tan (x)

p ro v e tan (x) csc (x) sec (x) = tan^{2} (x) + 1

p ro v e \frac{1}{cos ( - x )} - tan (- x) sin (- x) = cos (x)

p ro v e cos (1 5^{\circ}) = cos (4 5^{\circ} - 3 0^{\circ})

Is sin(x)cos(x)+sin(3x)sec(x)=tan(x) ?
The answer to whether sin(x)cos(x)+sin(3x)sec(x)=tan(x) is False